The diagonals of a parallelogram bisect each other.

DH = HF and GH = HE

x + 5 = 2y
3x - 1 = 5y + 4

Solve the first equation for x.
x = 2y - 5

Now substitute 2y - 5 for x in the second equation.

3(2y - 5) - 1 = 5y + 4

6y - 15 - 1 = 5y + 4

6y - 16 = 5y + 4

y = 20

Now substitute 20 for y in the first original equation.

x + 5 = 2y

x + 5 = 2(20)

x + 5 = 40

x = 35

Answer: x = 35 and y = 20

4 0

3 years ago

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The area of a triangle is found by multiplying half of the measure of its base by its height. The area of the following right tr

Scrat [10]

Answer:

AREA OF TRAINGLE =18

WE NO THE AREA OF 1/2 BH

B=6

PLUGGING IN THE VALUES

18 1/2 6 (H+1)

6=H+1

H=5

7 0

3 years ago

What would the answer for this question be

Yakvenalex [24]

THE ANSWER IS SIN C SOH OPPosit out of hypo

5 0

3 years ago

12. What is the length of SQ? F.5 H.13 G.9 J.17​

12. What is the length of SQ? F.5 H.13 G.9 J.17