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Nostrana [21]
2 years ago
7

Draw vectors to represent these motions:moving 3 cm to the rightmoving 2 cm to the left

Physics
1 answer:
Ira Lisetskai [31]2 years ago
7 0
Vector. Oh yeeeeeeeeahhh
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Can someone answer this please I’ll give brainliest
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Answer:

The last one is false

Explanation:

Energy can be neither created or destroyed. It can only move from one type of energy to another.

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According to the principal of wave refraction, when light from the atmosphere enters a medium of greater density at an oblique a
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d. velocity slows down and angle changes

Explanation:

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What happens to the water particles in a wave?
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A man, holding a weight in each hand, stands at the center of a horizontal frictionless rotating turntable. The effect of the we
Alex_Xolod [135]

Answer:

 w = 2w₀     the angular velocity of man doubles

Explanation:

In this exercise, releasing the weights reduces the moment of inertia

       I= I₀ / 2

Therefore, since the platform system plus man is isolated, the kinetic moment must be conserved

         L₀ = L

       I₀ w₀ = I w

       I₀ w₀ = I₀ / 2 w

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7 0
3 years ago
At what speed, as a fraction of c , is a particle's total energy twice its rest energy
WINSTONCH [101]
The rest energy of a particle is
E_0=m_0 c^2
where m_0 is the rest mass of the particle and c is the speed of light.

The total energy of a relativistic particle is
E=mc^2 =  \frac{m_0 c^2}{ \sqrt{1- \frac{v^2}{c^2} } }
where v is the speed of the particle.

We want the total energy of the particle to be twice its rest energy, so that
E=2E_0
which means:
\frac{m_0c^2}{ \sqrt{1- \frac{v^2}{c^2} } }=2m_0 c^2
\frac{1}{ \sqrt{1- \frac{v^2}{c^2} } }=2
From which we find the ratio between the speed of the particle v and the speed of light c:
\frac{v}{c}=  \sqrt{1- (\frac{1}{2})^2 }  =0.87
So, the particle should travel at 0.87c in order to have its total energy equal to twice its rest energy.
3 0
3 years ago
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