Answer:
0.24 kg used up
Explanation:
He has a mass of 67 kg
The gravitational constant is 9.81 m/s^2
The distance upward is 3500 m
W = m*g*h
W = 67 * 9.81 * 3500
Work = 2,300,445 Joules
Work = 2300 kj
work = 2.30 * 10^6 joules in scientific notation.
Part B
He needs 4 times this amount to climb the mountain because the body is only 25% efficient in converting energy.
4*2.30 * 10^6 = 9.20 * 10^6 Joules of energy are therefore required.
The total amount in a kg of fat = 3.8 * 10^7 joules
x kg of fat is needed to provide 9.20.*10^6 joules
1 kg / (3.8 * 10^7 J ) = x kg / (9.20 * 10^6 J)
9.20 * 10 ^6 * 1 = 3.8 * 10^7 *x
9.20 * 10 ^6 / 3.8 * 10^7 = x
x = 0.24 kg of fat are needed
(360 degrees) / (24hours) = 15 degrees/hour = 1 degree / 4minutes
The first and third choices on the list will attract, because UNlike poles are facing across the gap.
Choice #1: . . . [S]-----[N] . . . [S]-----[N]
Choice #3: . . . [N]-----[S] . . . [N]-----[S]
Yeah oppp because this is yes
A good way to do that is to talk abt anything, TALK MORE NOT LESS:)