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Romashka [77]
3 years ago
5

An astronaut in space pushes a piece of equipment to get it into the correct position. What does Newton's third law of motion te

ll us about this? Question 5 options: The equipment would have accelerated much faster if the astronaut had applied a much greater force to it. The equipment will "push back" on the astronaut with the same amount of force. The equipment would have stayed in the same exact location indefinitely until the very moment the astronaut applied force to it. The equipment will continue moving in the same direction indefinitely unless another force is applied to stop it.
Physics
2 answers:
Agata [3.3K]3 years ago
7 0

Answer: C and D

The equipment would have stayed in the same exact location indefinitely until the very moment the astronaut applied force to it.

The equipment will continue moving in the same direction indefinitely unless another force is applied to stop it.

Explanation: According to Newton's first law of motion which state that; A body at rest will continue to be at rest, or in linear motion will continue to move in a straight line, unless an external force act on it.

The equipment would have stayed in the same exact location indefinitely until the very moment the astronaut applied force to it.

immediately the astronaut apply force to the object by pushing in, Newton's first law will be manifested in which the equipment will continue moving in the same direction indefinitely unless another force is applied to stop it.

Alisiya [41]3 years ago
7 0

Answer:

its the equipment will "push back" on the astronaut the the same amount of force. i just took the test and thats what it said was the right answer was

Explanation:

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The radius of curvature is smaller at the top than on the sides so that the downward centripetal acceleration at the top will be
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Answer:

v = 14.86 m/s

Explanation:

As we know that the force equation at the top is given as

\frac{mv^2}{R} = ma

now we know that

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so we have

\frac{v^2}{R} = 1.5 g

v = \sqrt{1.5 Rg}

so we will have

v = \sqrt{1.5(15)(9.81)}

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The length of the solar day will get shorter.

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A boy throws a ball of mass 0.22 kg straight upward with an initial speed of 29 m/s. When the ball returns to the boy, its speed
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Answer:

The work is -67.76 J

Explanation:

The law of conservation of energy is considered one of one of the fundamental laws of physics and states that the total energy of an isolated system remains constant. except when it is transformed into other types of energy.

This is summed up in the principle that energy can neither be created nor destroyed in the universe, only transformed into other forms of energy.

In this case you must calculate the loss of kinetic energy. This loss is actually the work done against the resistive force in the air. Friction is the only force other than gravity that acts on the ball.

So, the loss of kinetic energy is \frac{1}{2} *m*(vf^{2} -vi^{2} )

You know:

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Final velocity of the ball: vf= 15 \frac{m}{s}

Replacing:

\frac{1}{2} *0.22 kg*(15^{2} -29^{2} )= -67.76 J

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