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Romashka [77]
3 years ago
5

An astronaut in space pushes a piece of equipment to get it into the correct position. What does Newton's third law of motion te

ll us about this? Question 5 options: The equipment would have accelerated much faster if the astronaut had applied a much greater force to it. The equipment will "push back" on the astronaut with the same amount of force. The equipment would have stayed in the same exact location indefinitely until the very moment the astronaut applied force to it. The equipment will continue moving in the same direction indefinitely unless another force is applied to stop it.
Physics
2 answers:
Agata [3.3K]3 years ago
7 0

Answer: C and D

The equipment would have stayed in the same exact location indefinitely until the very moment the astronaut applied force to it.

The equipment will continue moving in the same direction indefinitely unless another force is applied to stop it.

Explanation: According to Newton's first law of motion which state that; A body at rest will continue to be at rest, or in linear motion will continue to move in a straight line, unless an external force act on it.

The equipment would have stayed in the same exact location indefinitely until the very moment the astronaut applied force to it.

immediately the astronaut apply force to the object by pushing in, Newton's first law will be manifested in which the equipment will continue moving in the same direction indefinitely unless another force is applied to stop it.

Alisiya [41]3 years ago
7 0

Answer:

its the equipment will "push back" on the astronaut the the same amount of force. i just took the test and thats what it said was the right answer was

Explanation:

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Let's use trigonometry to find the component of the forces, let's use a reference frame where the x-axis coincides with the East and the y-axis coincides with the North.

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         sin 30 = F_{2y} / F₂

          F₂ₓ = F₂ cos 30

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        Fₓ = F₁ₓ + F₂ₓ

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to find the vector we use the Pythagorean theorem

         F = \sqrt{F_x^2 +F_y^2}

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the address is

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         θ = tan⁻¹ \frac{F_y}{F_x}

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         θ = 9.6º

the resultant force to two significant figures is

         F = 3.6 kN

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