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Gwar [14]
3 years ago
5

Can someone please help me with this question thank you!

Physics
1 answer:
katovenus [111]3 years ago
7 0
<h2>at the highest point that is B</h2><h2>because PE is directly proportional to height </h2><h2>hope it helped</h2>

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How does universal gravitation affect you and objects around you?
Olegator [25]

<u>Answer</u>:

Newton proposed the "law of Universal Gravitation". He said that gravity is universal in nature and it affects all the objects. Gravity is present between you and every object having mass around you. The "Strength of the gravity" between two objects with mass is depends on the product of masses and distance between the objects.

The "Gravitational force" increases with the increase in mass of the objects and decreases with the increase in distance between the objects. The gravity exerts a force on every object. The direction of force of gravity is towards the centre of the Earth.  

 

8 0
3 years ago
In March 2006, two small satellites were discovered orbiting Pluto, one at a distance of 48,000 km and the other at 64,000 km. P
Natasha_Volkova [10]

Answer

given,

distance of first satellite = 48,000 Km

distance of second satellite = 64,000 Km

orbital period = 6.39 day

Using equation of time period

  T = \dfrac{2\pi r^{3/2}}{\sqrt{Gm_{pluto}}}

now, from the above equation we can say that only variable is Time period and r is the radii of orbit.

from the first satellite

   \dfrac{T_{charon}}{r^{3/2}_{charon}}=\dfrac{T_{sat1}}{r^{3/2}_{sat1}}

   T_{sat1}=\dfrac{T_{charon}\ r^{3/2}}{r^{3/2}_{charon}}

   T_{sat1}=\dfrac{6.39\times (48000)^{3/2}}{19600^{3/2}}

   T_{sat1}=24.5\ days

for second satellite

   T_{sat2}=\dfrac{T_{charon}\ r^{3/2}_{sat2}}{r^{3/2}_{charon}}

   T_{sat1}=\dfrac{6.39\times (64000)^{3/2}}{19600^{3/2}}

   T_{sat1}=37.7\ days

7 0
3 years ago
I need help pleaseee
Ludmilka [50]

Answer:

8) 709.8875 J

9) The object is at 7.24375 m from the ground

10) Kinetic energy increases as the object falls.

Explanation:

We use the expression for the displacement h(t) as a function of time of an object experiencing free fall:

h(t) = hi - (g/2) t^2

hi being the initial position of the object (10m) above ground, g the acceleration of gravity (9.8 m/s^2), and t the time (in our case 0.75 seconds):

h(0.75) = 10 - 4/9 (0.75)^2 = 7.24375 m

This is the position of the 10 kg object after 0.75 seconds (answer for part 9)

Knowing this position we can calculate the potential energy of the object when it is at this height, using the formula:

U = m g h = 10kg * 9.8 (m/s^2) * 7.24375 m = 709.8875 J (answer for part 8)

Part 10)

the kinetic energy of the object increases as it gets closer to ground, since its velocity is increasing in magnitude because is being accelerated in its motion downwards.

3 0
3 years ago
Write a small paragraph on how to determine the speed of sound using the time of flight method.
Makovka662 [10]

Answer:

time of flight of a pulse, and these most often

involve triggering of the measuring oscilloscope

with the signal that generates the sound pulse and

timing the time delay of the pulse picked up by a

conveniently placed microphone4­5

. Loren Winters

has reported a method similar in principle to the

present one, but which uses a completely different

detection system6

.

Explanation:

6 0
3 years ago
A red racecar accelrates at a constant rate of 5 m/s2. How much time does it take to increase its speed from 50 m/s to 60 m/s?
natulia [17]
A red racecar accelrates at a constant rate of 5 m/s2. How much time does it take to increase its speed from 50 m/s to 60 m/s?


A.17 s


B.0.058 s


C.0.25 s


D.2.0 s
7 0
3 years ago
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