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Daniel [21]
3 years ago
9

Help now!!!!!! brainliest and 15 points Which of the following relations is not a function ​

Mathematics
2 answers:
exis [7]3 years ago
5 0

Answer:

THe 1 st one

Step-by-step explanation:

hope this helps

lys-0071 [83]3 years ago
3 0

Answer:

1

Step-by-step explanation:

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-5|x+1|=10 solve for x
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Answer:

x=-3

Step-by-step explanation:

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Given a function f(x)=2x^2+3, what is the average rate of change of f on the interval [2, 2+h]?
-Dominant- [34]
-8h - 2h^2

f(2)-f(2+h) = -8h - 2h^2


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Solve by using the square root property. Write your answer in simplest radical form.
ELEN [110]

Answer: X = t or minus 4 square root 3 and X= 4 square root 3 Explanation: add 48 on both sides bring down x squared = 48 take the square root on both sides you get X= t or - 4 square root 3 and X=4 square root 3) Animex yw

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One of the legs of a right triangle measures 6 cm and its hypotenuse measures 8 cm. Find the measure of the other leg. If necess
Vika [28.1K]
Well, this is a Pythagorean theorem problem. A^2 + B^2 = C^2, where C^2 is equal to the hypotenuse. 8 squared equals 64, so c^2 = 64 cm. The other leg can be represented by A^2, which is 36 cm. 36 + ? = 64. 64 - 36 = 28, so B^2 equals 28. Now, to find the measurement of the other leg, we need the square root of 28. The square root of 28 is 5.3 cm.

Your final answer is 5.3 cm.
8 0
2 years ago
Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of
alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

  (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

- The standard form of the linear equation is Ax + BC = C, where

  A , B , C are integers and A , B ≠ 0

- The median of a trapezoid is a segment that joins the midpoints of

 the nonparallel sides

- It has two properties:

# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

 parallel bases and which of them are the non-parallel bases

# The side RS

∵ m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}

# The side ST

∵ m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}

# The side TU

∵ m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}

# The side UR

∵ m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

 median of the trapezoid

∵ The median of a trapezoid is a segment that joins the midpoints of

   the nonparallel sides

∵ The midpoint of RS = (\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

- To find c substitute x , y in the equation by the coordinates of the

  midpoint of RS  

∵ The mid point of Rs is (0 , 13/2)

∴ 13/2 = -5/3 (0) + c

∴ 13/2 = c

∴ The equation of the median is y = -5/3 x + 13/2

- Multiply the two sides by 6 to cancel the denominator

∴ The equation of the median is 6y = -10x + 39

- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

7 0
3 years ago
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