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nalin [4]
4 years ago
14

Problem 1: A catchment has the following Horton’s infiltration parameters: f0=280 mm/hr, fc=25 mm/hr and k = 2.5 hr-1 . For the

rainfall distribution is given below Interval (mins) 0-10 10-20 20-30 30-40 40-50 Rainfall (mm/hr) 25 50 80 205 170 (a) What is the cumulative infiltration rate (F), infiltration rate (fp), depression storage (S) and runoff (R) at each time step (b) What time does ponding occur?

Engineering
1 answer:
harkovskaia [24]4 years ago
6 0

Answer:

Ponding will occur in 40mins

Explanation:

We say that the infiltration rate is the velocity or speed at which water enters into the soil. This often times is measured by the depth (in mm) of the water layer that can enter the soil in one hour. An infiltration rate of 15 mm/hour means that a water layer of 15 mm on the soil surface, will take one hour to infiltrate.

Consider checking attachment for the step by step solution.

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cloud storage is the answer

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3 years ago
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Feliz [49]
<h2>Answer:-</h2>

1.Enzymes used by fireflies are used to improve <u>Food Safety </u><u>.</u>

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3 0
3 years ago
Assume that each atom is a hard sphere with the surface of each atom in contact with the surface of its nearest neighbor. Determ
deff fn [24]

Answer:

The classification of the concern is listed in the interpretation segment below.

Explanation:

(a)...

<u>Simple cubic lattice</u>

<u />a=2r

Now,

The unit cell volume will be:

=a^3

=(2r)^3

=8r^3

At one atom per cell, atom volume will be:

=(1)\times (\frac{4 \pi r^3}{3})

Then the ratio will be:

Ratio=\frac{\frac{4 \pi r^3}{3}}{8r^3}\times 100 \ percent

        =52.4 \ percent

(b)...

<u>Diamond lattice</u>

The body diagonal will be:

d=8r=a\sqrt{3}

       a=\frac{8}{\sqrt{3}}r

The unit cell volume will be:

=a^1

=(\frac{8r}{\sqrt{3}})^1

At eight atom per cell, the atom volume will be:

=8(\frac{4 \pi r^1}{3})

Then the Ratio will be:

Ratio=\frac{8(\frac{4 \pi r^1}{3})}{(\frac{8r}{\sqrt{3}})^1}\times 100 \ percent

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Note: percent = %

5 0
3 years ago
When changing a tire size 195/75 R15 to a 5 percent lower profile, the correct tire size would be
loris [4]

Answer:

205/70 R15

Explanation:

The change of sizes is determined a formula which changes tire to 5% lower profile with 10 mm wider cross section. This implies that the reducing aspect ratio is 5. Now, adding 10 to 195 makes it 205 but subtracting 5 from 75 making it 70. By changing the tire size of 195/75 R15 using the this formula, this will be changed to size of 205/70 R15. Therefore, the right option is 205/70 R15.

3 0
3 years ago
A precision miling machince wighing 1000lb is supported on a rubber mount. The force deflection relationship of the rubber mount
Alisiya [41]

Answer:

0.2846 in

Explanation:

The static equilibrium position of the rubber mount ( x^*), under the weight of the milling machine,  can be determined from:

1000=3500(x^*)+ 55(x^*)^3\\\\55(x^*)^3+ 3500x^*-1000=0\\\\Solving\ for\ the\ roots\ using \ a \ calculator\ or\ matlab\ gives:\\ \\x^*_1=0.28535\\x^*_2=-0.14267+7.89107i\\x^*_3=-0.14267-7.89107i\\\\We\ are\ using\ the \ real\ root\ which\ is\ x^*_1=0.28535\\

k=\frac{dF}{dx}|_{x^*}\\ \\k=\frac{d}{dx}(3500x+55x^3)|_{x^*}\\\\k=3500+165x^2|_{x^*}\\\\k=3500+165(x^*)^2\\\\k=3500+165(0.28535)^2=3513.435\ lb/in

The static equilibrium position is at:

x=\frac{F}{k}=\frac{1000}{3513.435}  =0.2846\ in

8 0
3 years ago
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