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nadezda [96]
3 years ago
6

Match the word with the definition:

Engineering
2 answers:
aksik [14]3 years ago
7 0

1. Renewable Resources  = (Renewable means you can keep making it) =  resources that can be replenished (such as trees)

2. Nonrenewable Resources  =  ( Nonrenewable means it can't be made once it is used up) = resources that are gone once they are used (such as fossil fuels)

3. Producer  =  ( produces something) = person who makes goods or provides services

4. Consumer  = ( uses something) =   person whose wants are satisfied by using goods and services

5. Allocate  = ( put someplace) =   distribute

6. Choice =  option

Pachacha [2.7K]3 years ago
3 0

Answer:

Those are by definition so I do not have any explanation.

Explanation:

person whose wants are satisfied by using goods and services

4. Consumer

resources that can be replenished (such as trees)

1. Renewable Resources

option

6. Choice

person who makes goods or provides services

3. Producer

resources that are gone once they are used (such as fossil fuels)

2. Nonrenewable Resources

distribute

5. Allocate

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Find R subscript C and R subscript B in the following circuit such that BJT would be in the active region with V subscript C E e
Alex777 [14]

Answer: Rc = 400 Ω and Rb = 57.2 kΩ

Explanation:

Given that;

VCE = 5V

VCC = 15 V

iC = 25 mA

β = 100

VD₀ = 0.7 V

taking a look at the image; at loop 1

-VCC + (i × Rc) + VCE = 0

we substitute

-15 + ( 25 × Rc) + 5 = 0

25Rc = 10

Rc = 10 / 25

Rc = 0.4 k

Rc = 0.4 × 1000

Rc = 400 Ω

iC = βib

25mA = 100(ib)

ib = 25 mA / 100

ib = 0.25 mA

ib = 0.25 × 1000

ib = 250 μAmp

Now at Loop 2

-Vcc + (ib×Rb) + VD₀ = 0

-15 (250 × Rb) + 0.7 = 0

250Rb = 15 - 0.7

250Rb = 14.3

Rb = 14.3 / 250

Rb = 0.0572 μ

Rb = 0.0572 × 1000

Rb = 57.2 kΩ

Therefore Rc = 400 Ω and Rb = 57.2 kΩ

8 0
3 years ago
A tensile test uses a test specimen that has a gage length of 50 mm and an area = 206 mm2. During the test, the specimen yields
vampirchik [111]

Answer:

The percent elongation in the length of the specimen is 42%

Explanation:

Given that:

The gage length of the original test specimen  L_o = 50 mm

The final gage length L_f = 71 mm

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maximum load  =  162,699 N

To determine the percent elongation in %, we use the formula:

\%EL = \dfrac{L_f-L_o}{L_o}\times 100

\%EL = \dfrac{71 \ mm-50 \ mm}{50 \ mm}\times 100

\%EL = \dfrac{21 mm}{50 \ mm}\times 100

\%EL = 0.42 \times 100

\mathbf{\%EL = 42 \%}

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