Answer:
input power of the geothermal motor will be 0.4166 hP
Explanation:
We have given shaft output = 0.25 hP
hP is known as horse power which is unit of measuring the power of motor
Efficiency of motor is given as efficiency = 60 % = 0.6
We have to fond the heat supply by the fan motor Q
We know that efficiency of any motor is the ratio of shaft power and input power
So
So 
So input power of the geothermal motor will be 0.4166 hP
Answer:
hello your question is incomplete attached below is the complete question
answer : Drag force = 1.3 Ib
Explanation:
we have to represent the dimensions of the drag force in terms of FLT
i.e : D = f( <em>d,v,p,u </em>) represented in terms of FLT
D = F , V = LT^-1, d = L, p = FL^-4 T^2
u = FL^-2 T, Number of independent terms = 5
attached below is the detailed solution
I put
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Answer: a) 0.948 b) 117.5µf
Explanation:
Given the load, a total of 2.4kw and 0.8pf
V= 120V, 60 Hz
P= 2.4 kw, cos θ= 80
P= S sin θ - (p/cos θ) sin θ
= P tan θ(cos^-1 (0.8)
=2.4 tan(36.87)= 1.8KVAR
S= 2.4 + j1. 8KVA
1 load absorbs 1.5 kW at 0.707 pf lagging
P= 1.5 kW, cos θ= 0.707 and θ=45 degree
Q= Ptan θ= tan 45°
Q=P=1.5kw
S1= 1.5 +1.5j KVA
S1 + S2= S
2.4+j1.8= 1.5+1.5j + S2
S2= 0.9 + 0.3j KVA
S2= 0.949= 18.43 °
Pf= cos(18.43°) = 0.948
b.) pf to 0.9, a capacitor is needed.
Pf = 0.9
Cos θ= 0.9
θ= 25.84 °
(WC) V^2= P (tan θ1 - tan θ2)
C= 2400 ( tan (36. 87°) - tan (25.84°)) /2 πf × 120^2
f=60, π=22/7
C= 117.5µf
The answer for this question is A