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4 years ago

30 points

2 answers:

8 0

The molecular weight for Calcium Chloride Dihydrate (CaCl2•2H20) is 2H2O.

mass of 64g/mol = 256.52 g/mol
mass of 11g/mol = 26.981538 g/mol
mass of 147g/mol= 146.9149 g/mol
258g/mol = 258.09843 g/mol

Tcecarenko [31]4 years ago

4 0

Answer:

$M=147.014 g/mol$

Explanation:

The atomic weights of the elements:

Ca=40.078 g/mol

Cl=35.453 g/mol

H=1.008 g/mol

O=15.999 g/mol

The calcium chloride dihydrate:

$M=(40.078+35.453*2+2*2*1.008+2*15.999)g/mol$

$M=147.014 g/mol$

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A fish tank holds 45 gal of water. How many kilograms of water are in the fish tank?

larisa [96]

Answer:

How to convert 45 gal to kg? You can use the following formula to convert from Gallon to Kilograms :

X(kg) = y(gal) / 0.264172053

To convert 45 Gallon to Kilograms:

X(oz) = 45(gal) / 0.264172053

Answer: 170.3435 kg

7 0

2 years ago

5. Which of these elements has the greatest atomic radius? *<br> Be<br> Mg<br> Ra<br> Ba

trapecia [35]

The answer is Ra
Atomic number for Be is 4

Atomic number for Mg 12

Atomic number for Ra 88

Atomic number for Ba 56

5 0

3 years ago

Predict how many grams of KCI is produced from 40 grams of K?

Nutka1998 [239]

Explanation:

firstly find for the molar mass of kcl and molar mass of k

and then

molar mass of k = x

molar mass of kcl= 40

cross mutiply and then simplify you will get your answer

5 0

4 years ago

4. A student started with a 0.032 g sample of copper which he took through the series of reactions described in this experiment.

Elodia [21]

Answer:

$Y=48.6\%$

Explanation:

Hello,

In this case, we can consider the following chemical reaction for the oxidation of copper which only occurs at high temperatures:

$2Cu+O_2\rightarrow 2CuO$

In such a way, for 0.032 grams of copper, the following grams of copper (II) oxide (black product) are yielded:

$m_{CuO}=0.032gCu*\frac{1molCu}{63.546gCu} *\frac{2molCuO}{2molCu}*\frac{79.546gCuO}{1molCuO} =0.078gCuO$

Therefore, the percent yield is:

$Y=\frac{0.038g}{0.078g}*100\%\\ \\Y=48.6\%$

Best regards.

6 0

3 years ago

Be sure to answer all parts. Butane gas is compressed and used as a liquid fuel in disposable cigarette lighters and lightweight

Salsk061 [2.6K]

Answer:

The correct answer will be "4.60 g".

Explanation:

The given values are:

Volume of Butane = 7.96 mL

Density = 0.579 g/mL

As we know,

⇒ $Mass \ of \ Butane = Density\times Volume$

On putting the estimated values, we get

⇒ $=0.579\times 7.96$

⇒ $=4.60 \ g$

6 0

3 years ago