30 points

2 answers:

8 0

The molecular weight for Calcium Chloride Dihydrate (CaCl2•2H20) is 2H2O.

mass of 64g/mol = 256.52 g/mol
mass of 11g/mol = 26.981538 g/mol
mass of 147g/mol= 146.9149 g/mol
258g/mol = 258.09843 g/mol

Tcecarenko [31]3 years ago

4 0

Answer:

$M=147.014 g/mol$

Explanation:

The atomic weights of the elements:

Ca=40.078 g/mol

Cl=35.453 g/mol

H=1.008 g/mol

O=15.999 g/mol

The calcium chloride dihydrate:

$M=(40.078+35.453*2+2*2*1.008+2*15.999)g/mol$

$M=147.014 g/mol$

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How many moles of AlCl3 are formed by 1.53 moles of CuCl2?

jolli1 [7]

Answer:

1.02 moles of AlCl3

Explanation:

Consider the balanced reaction equation shown below;

2Al(s) + 3CuCl2(aq) -------> 2AlCl3 (aq) + 3Cu(s)

This is the balanced reaction equation for the reaction going on above. Recall that the first step in solving any problem is to accurately put down the chemical reaction equation. This balanced reaction equation always serves a reliable guide in solving the problem at hand.

Given that;

3 moles of CuCl2 yields 2 moles of AlCl3

1.53 moles of CuCl2 yields 1.53 × 2 / 3 =1.02 moles of AlCl3

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