Answer:
The standard cell potential of the reaction is 0.78 Volts.
Explanation:

Reduction at cathode :
Reduction potential of
to Cu=
Oxidation at anode:

Reduction potential of
to Fe=
To calculate the
of the reaction, we use the equation:

Putting values in above equation, we get:

The standard cell potential of the reaction is 0.78 Volts.
Answer: 0.8541 grams of HCl will be required.
Explanation: Moles can be calculated by using the formula:

Given mass of
= 0.610 g
Molar mass of
= 78 g/mol

Number of moles of
= 0.0078 moles
The reaction between
and HCl is a type of neutralization reaction because here acid and base are reacting to form an salt and also releases water.
Chemical equation for the above reaction follows:

By Stoichiometry,
1 mole of
reacts with 3 moles of HCl
So, 0.0078 moles of
will react with
= 0.0234 moles
Mass of HCl is calculated by using the mole formula, we get
Molar mass of HCl = 36.5 g/mol
Putting values in the equation, we get
Mass of HCl required will be = 0.8541 grams
Answer: 6.26atm
Explanation:Please see attachment for explanation