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tamaranim1 [39]
3 years ago
7

How do I do this???

Chemistry
1 answer:
Monica [59]3 years ago
4 0
The chemical reaction is as follows:

<span>2NH3(g) = N2(g) + 3H2(g)

We do the ice method to answer this. 
                
            NH3            N2             H2
I          1.22              0                0
C          -2x              x                3x 
E        1.22 - 2x       x                3x

Kc = [h2]^3 [n2] / [nh3]^2
</span>4.0 × 10^–2 = 27x^3(x) /  (1.22 - 2x )^2
x = 0.259 mol

H2 = 0.259/1 = 0.259 mol/L
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3 years ago
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A sample of neon gas in a bulb is at 149.05 °C and 349.84 kPa. If the pressure drops
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<h3>Data obtained from the question </h3>
  • Initial temperature (T₁) = 149.05 °C = 149.05 + 273 = 422.05 K
  • Initial pressure (P₁) = 349.84 KPa
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<h3>How to determine the new temperature </h3>

The new temperature of the gas can be obtained by using the combined gas equation as illustrated below:

P₁V₁ / T₁ = P₂V₂ / T₂

Since the volume is constant, we have:

P₁ / T₁ = P₂ / T₂

349.84 / 422.05 = 103.45 / T₂

Cross multiply

349.84 × T₂ = 103.45 × 422.05

Divide both side by 349.84

T₂ = (103.45 × 422.05) / 349.84

T₂ = 124.80 K

Subtract 273 from 124.80 K to express in degree celsius

T₂ = 124.80 – 273

T₂ = –148.20 °C

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