I'm pretty sure the answer would be that the metal is conductive, which travels through the copper wires.
Chemical reaction of PO₄³⁻ ion in water:
PO₄³⁻(aq) + H₂O(l) → HPO₄²⁻(aq) +OH⁻(aq).
Kb = [HPO₄²⁻] · [OH⁻] / [PO₄³⁻]; <span>base ionization constant.
</span>Base ionization constant <span>is the equilibrium </span>constant<span> for the </span>ionization<span> of a </span>base<span>.
</span>According
to Bronsted-Lowry theory acid are donor of protons and bases are
acceptors of protons (the hydrogen cation or H⁺<span>).
</span>PO₄³⁻ is Bronsted base and it can accept proton and
become conjugate acid HPO₄²⁻.
Answer:
ΔH3 = 1/2 (629) - ΔH^0
Explanation:
Given data:
Bond energy of H2 = ΔH1 = 436 Kj/mol
Bond energy of Br2 = ΔH2 = 193 Kj/mol
To find:
Let bond energy of HBr = ΔH3 = ?
Equation:
H2 + Br2 → 2HBr
enthalpy of formation of HBr = ΔH1 + ΔH3 - 2(ΔH3)
ΔH^0 = 436 + 193 - 2(ΔH3)
(436 + 193) - ΔH^0 = 2(ΔH3)
ΔH3 = 1/2 (629) - ΔH^0
Answer:
The correct answer is C 112
Explanation:
I just took the test good luck :)
