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Marrrta [24]
3 years ago
13

The average American student is in class 330 minutes/day. How many hours/day is this?

Chemistry
1 answer:
mezya [45]3 years ago
7 0
330 divided by 60 minutes per hour gives us 5.5 hours/day
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Quick help I really need help
Sauron [17]

Answer:

CO2 H2o

Explanation:

8 0
3 years ago
how to identify amphiprotic compounds, if i give you the chemical structure or name of the compound/molecule.
Sonja [21]

Amphiprotic compounds are able to both donate and accept a proton.

Amphiprotic compounds contain a hydrogen atom and lone pair of valence electron.

For example, HSO₃⁻ (hydrogen sulfate ion) is an amphiprotic compound.

Balanced chemical equation for reaction when HSO₃⁻ donate protons to water:

HSO₃⁻(aq) + H₂O(l) ⇄ SO₄²⁻(aq) + H₃O⁺(aq).

Ka = [SO₄²⁻] · [H₃O⁺] / [HSO₃⁻]

Balanced chemical equation for reaction when HSO₃⁻ accepts protons from water:

HSO₃⁻(aq) + H₂O(l) ⇄ H₂SO₄(aq) + OH⁻(aq).

Kb = [H₂SO₄] · [OH⁻] / [HSO₃⁻]

Water (H₂O), amino acids, hydrogen carbonate ions (HCO₃⁻) are examples of amphiprotic species.

Another example, water is an amphiprotic substance:

H₂O + HCl → H₃O⁺ + Cl⁻

H₂O + NH₃ → NH₄⁺ + OH⁻

More about amphiprotic compounds: brainly.com/question/3421406

#SPJ4

7 0
1 year ago
calculate the wavelength of light associated with the transition from n=1 to n=3 in the hydrogen atom?
inessss [21]

<u>Answer:</u>

\Delta E=E_{final}-E_{initial}

\Delta E=-1312[\frac{1}{(n_f^2)}-\frac {1}{(n_i^2 )}]KJ mol^{-1}

\Delta E=-1312[\frac{1}{3^2)}-\frac {1}{(1^2 )}]KJ mol^{-1}

\Delta E=-1312[\frac{1}{(9)}-\frac {1}{(1 )}]KJ mol^{-1}

\Delta E=-1312[0.111-1]KJ mol^{-1}

\Delta E=1166 KJ mol^{-1}

\frac{=1166,000 \mathrm{J}}{6.022 \times 10^{23} \text { photons }}

=193623 \times 10^{-23}  \frac {J}{photon}

\Delta E=1.93623 \times 10^{-18}  \frac {J}{photon}

\Delta E=\frac {h\times c}{\lambda} \\\\=\frac {(6.626\times 10^{-34} J s \times 3 \times 10^8 ms^{-1})}{\lambda}

h is planck's constant  

c is the speed of light

λ is the wavelength of light  

\lambda =\frac {h\times c}{\Delta E}\\\\=\frac {(6.626\times10^{-34} J s\times3 \times 10^8 ms^{-1})}{(1.93623\times10^{-18}  J/photon)}

Wavelength

\lambda =10.3 \times 10^{-8} m \times \frac {(10^9 nm)}{1m}  =103 nm (Answer)

<em>Thus, the wavelength of light associated with the transition from n=1 to n=3 in the hydrogen atom is </em><u><em>103 nm.</em></u>

7 0
2 years ago
Scientists in ____ discover new products and processes and improve current technology.
klasskru [66]

I think the answer is research and development.
7 0
3 years ago
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A flower's color is a trait that is passed from one generation to the next generation. How a trait such as flower color is physi
klemol [59]
I think it’s A (don’t take my word for it just consider that one greatly)
3 0
2 years ago
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