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Dominik [7]
3 years ago
7

Jesse drives to work. The distance Jesse’s car travels (d) on a number of gallons of gas (g) is given by the equation d = 15g. T

he constant of proportionality in terms of distance traveled per gallon of gas is?
Mathematics
1 answer:
kirill115 [55]3 years ago
4 0
I can only half answer this question, as it doesn't tell what form of distance is used

the equation is...

d=15g

Now lets solve for 1 gallon of gas

d=15g
d=15(1)
d=15

This means that for every 1 gallon of gas, 15 (insert missing unit of distance here) can be driven.

15/1=15

Answer:The constant of proportionality is 15.


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I need help with this please. :)
jek_recluse [69]

9514 1404 393

Answer:

  1. 2x
  2. 2
  3. 128x +640

Step-by-step explanation:

1.

  \displaystyle\frac{8x^2-4x}{4x-2}=\frac{4x(2x-1)}{2(2x-1)}=\boxed{2x}

__

2.

  \displaystyle\frac{8x-4}{x+3}-\frac{12x-20}{2x+6}=\frac{8x-4}{x+3}-\frac{4(3x-5)}{2(x+3)}=\frac{8x-4-2(3x-5)}{x+3}\\\\=\frac{8x-4-6x+10}{x+3}=\frac{2x+6}{x+3}=\frac{2(x+3)}{x+3}=\boxed{2}

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3.

  \displaystyle\frac{(2x+10)^7}{(x+5)^6}=\frac{(2(x+5))^7}{(x+5)^6}=2^7(x+5)^{7-6}=128(x+5)\\\\=\boxed{128x+640}

5 0
3 years ago
Find the common ratio of the geometric sequence 13,39,117
Anna [14]

r = 39/13 = 3

check

117 /39 = 3

true


so r=3

7 0
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A square pyramid has sides of 4.1 cm, and a pyramid height of .6 cm, determine the volume.
Rainbow [258]
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Read 2 more answers
Write a two-column proof. Given: line BD bisects angle CBE. Prove: angle ABD approximately equal to angle FBD.
ale4655 [162]

Answer:

The proof is derived from the summarily following equations;

∠FBE + ∠EBD = ∠CBA + ∠CBD

∠FBE + ∠EBD = ∠FBD

∠CBA + ∠CBD = ∠ABD

Therefore;

∠ABD ≅ ∠FBD

Step-by-step explanation:

The two column proof is given as follows;

Statement {}                                       Reason          

\underset{BD}{\rightarrow} bisects ∠CBE {}                            Given

Therefore;

∠EBD ≅ ∠CBD  {}                              Definition of angle bisector

∠FBE ≅ ∠CBA {}                                Vertically opposite angles are congruent

Therefore, we have;

∠FBE + ∠EBD = ∠CBA + ∠CBD {}     Transitive property

∠FBE + ∠EBD = ∠FBD {}                    Angle addition postulate

∠CBA + ∠CBD = ∠ABD {}                   Angle addition postulate

Therefore;

∠ABD ≅ ∠FBD        {}                          Transitive property.

3 0
3 years ago
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