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Assoli18 [71]
3 years ago
5

In a chemical reaction, the products are

Chemistry
2 answers:
Blizzard [7]3 years ago
6 0

whatever u r mixing together will indicated what the reaction or the product will be

Licemer1 [7]3 years ago
4 0

Answer:

Products are ALWAYS to the right.

Explanation:

Your products will ALWAYS be to the right of the equation, your reactants will ALWAYS be to the left of the equation. The reactants are changed into the product.

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HELP! Answer the question below PLEASE
garri49 [273]

Answer: Francesco Redis Experiment part 1 : The maggots were not observed in setup B and setup C because the jars were covered.

part 2 : He discovered that maggots appeared on the meat in the control jar, the jar left open. No maggots appeared in the jar covered with gauze.

Pasteur Experiment

part 1:In the pastures Experiment the microorganisms come from the air.

part 2:Louis Pasteur's pasteurization experiment illustrates the fact that the spoilage of liquid was caused by particles in the air rather than the air itself.

Explanation:

8 0
2 years ago
What will the subscript for NH4 be?
alisha [4.7K]

Answer:

2

Explanation:

The subscript on Ammoniumwhich is (NH4) is 2.

Hope this helped!

4 0
2 years ago
Who developed the orbital model of the atom?
Nataliya [291]

Answer:

Ernest Rutherford

Explanation:

that's I think

7 0
2 years ago
How many atoms are in an Apple
miss Akunina [59]

Answer:10^27 atoms in an apple

Explanation:

3 0
2 years ago
1.00 g of a compound is combusted in oxygen and found to give 3.14g of CO2 and 1.29 g of H2O. From these data we can tell thatA.
lora16 [44]

Answer:

the compound contains C, H, and some other element of unknownidentity, so we can’t calculate the empirical formula

Explanation:

Mass of CO2 obtained = 3.14 g

Hence number of moles of CO2 = 3.14g/44.0 g = 0.0714 mol

The mass of the carbon in the sample = 0.0714 mol × 12.0g/mol = 0.857 g

Mass of H2O obtained = 1.29 g

Hence number of moles of H2O = 1.29g/18.0 g = 0.0717 mol

The mass of the carbon in the sample = 0.0717 mol × 1g/mol = 0.0717 g

% by mass of carbon = 0.857/1 ×100 = 85.7 %

% by mass of hydrogen = 0.0717/1 × 100 = 7.17%

Mass of carbon and hydrogen = 85.7 + 7.17 = 92.87 %

Hence, there must be an unidentified element that accounts for (100 - 92.87) = 7.13% of the compound.

5 0
3 years ago
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