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otez555 [7]
3 years ago
15

Here is the balanced chemical equation for the combustion of isopropyl alcohol: 2C3H7OH(l) + 9O2(g) → 6CO2(g) + 8H2O(g) Multiply

ing 42 by 2/3, or 0.667, would be most useful for which calculation?
A. Calculating the moles of O2 needed to produce 42 moles of CO2.

B. Calculating the moles of CO2 that will form from 42 moles of C3H7OH.

C. Calculating the moles of O2 that will react completely with 42 moles of C3H7OH.

D. Calculating the moles of CO2 that will form from 42 moles of O2.
Chemistry
2 answers:
Whitepunk [10]3 years ago
5 0
I believe the correct answer from the choices listed above is option A. Multiplying 42 by 2/3, or 0.667, would be most useful for c<span>alculating the moles of O2 needed to produce 42 moles of CO2. Hope this answers the question.</span>
Lelechka [254]3 years ago
3 0
Hello there.

<span>Here is the balanced chemical equation for the combustion of isopropyl alcohol: 2C3H7OH(l) + 9O2(g) → 6CO2(g) + 8H2O(g) Multiplying 42 by 2/3, or 0.667, would be most useful for which calculation?

</span><span>A. Calculating the moles of O2 needed to produce 42 moles of CO2.
</span>
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The temperature and number of moles of a gas are held constant. Which of the following is true for the pressure of the gas?
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Pressure is inversely proportional to the volume of gas.

Explanation:

According to Boyle's law,

The volume of given amount of gas is inversely proportional to the pressure applied on gas at constant volume and number of moles of gas.

Mathematical expression:

P ∝ 1/ V

P = K/V

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when volume is changed from V1 to V2 and pressure from P1 to P2 then expression will be.

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4 0
2 years ago
A. The half-life for a first order reaction in 49 minutes. What is the rate constant?B.For a second order reaction, the half-lif
Burka [1]

Answer:

a) 0,014 min⁻¹

b) 1452 seconds.

c) 0,02156 M

d) The faster rate is for the reaction A. The largest rate constant, k, is for A reaction

Explanation:

a) For a first order reaction the half-life is:

t_{1/2} = \frac{ln(2)}{k} <em>(1) </em>As half.life is 49 min. Rate constant -k- is: 0,014 min⁻¹

b) The half-life is defined as the time that takes in descompose the half of the initial concentration of a compound.

As half-life is 726s. In 726s the concentration will be 0,300M, In the next 726s the concentration will be 0,150M. Thus, thae time it takes to decrease concentration until 0,150M is 726s×2= 1452 seconds

c) In the same way, 11072 years are 4 half-life for this reaction, thus:

0,345M/2⁴ = 0,02156 M

d) By definition of half-life, the less half-life, the faster rate. Thus, The faster rate is for the reaction A.

By (1) half-life is inversely proportional to rate constant. Thus, the less half-life, the largest rate constant. The largest rate constant, k, is for A reaction

I hope it helps!

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