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Alexus [3.1K]
3 years ago
9

Period, block, and group

Chemistry
1 answer:
Sedaia [141]3 years ago
8 0

Answer:

what do you mean

Explanation:

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In a redux reaction why does an <br> element oxidation number decreases
Olin [163]

Answer:

Decreases

Explanation:

An element's oxidation number decreases because it gained electrons.

7 0
2 years ago
Calculate the percent activity of the radioactive isotope strontium-89 remaining after 5 half-lives.
maria [59]
The answer to this question would be: 3.125%

Half-life is the time needed for a radioactive molecule to decay half of its mass. In this case, the strontium-89 is already gone past 5 half lives. Then, the percentage of the mass left after 5 half-lives should be:
100%*(1/2^5)= 100%/32=3..125%
5 0
3 years ago
I need this ASAP thank you
Rainbow [258]

Answer:

16,,24Mg 17,,a24.1 18a mass number of the most abundant isotope

Explanation:

atomic number of Mg is 12 ,therefore its mass number should be the value that is very close to 24.

24.1 is the value of thee most abundant isotope.

8 0
2 years ago
Can some body plz help correct me or correct the true or false answers I did wrong. I’m not sure there right :(
3241004551 [841]

4 3 and 5 are wrong:)

4 is true and 5 is false

4. insulators are really thick materials that keep electrons within their space.

For example, a charger the rubber is the insulators and the electrons are flowing inside of the charger so you don't get shocked.

5. without the force of attraction, there are no atoms:)

for number 3, its a trick question

Hope this helped!

(learned these this year so I didn't forget them:)

8 0
2 years ago
A 13.00 g sample of citric acid reacts with an excess of baking soda What is the theoretical yield of carbon dioxide
viva [34]

Answer:

8.934 g

Step-by-step explanation:

We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:        192.12                                                                   44.01

            H₃C₆H₅O₇ + 3NaHCO₃ ⟶ Na₃C₆H₅O₇ + 3H₂O + 3CO₂

m/g:        13.00

For ease of writing, let's write H₃C₆H₅O₇ as H₃Cit.

(a) Calculate the <em>moles of H₃Cit </em>

n = 13.00 g  × (1 mol H₃Cit /192.12 g H₃Cit)

n = 0.067 67 mol H₃Cit

(b) Calculate the <em>moles of CO₂ </em>

The molar ratio is (3 mol CO₂/1 mol H₃Cit)

n = 0.067 67 mol H₃Cit × (3 mol CO₂/1 mol H₃Cit)

n = 0.2030 mol CO₂

(c) Calculate the <em>mass of CO₂ </em>

m = 0.2030 mol CO₂ × (44.01 g CO₂/1 mol CO₂)

m = 8.934 g CO₂

4 0
3 years ago
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