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Alexus [3.1K]
3 years ago
9

Period, block, and group

Chemistry
1 answer:
Sedaia [141]3 years ago
8 0

Answer:

what do you mean

Explanation:

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Did you write these compounds?<br> KBr<br> 2 NH₂OH<br> 2HNO3
Orlov [11]

The missing components of the neutralisation reaction include the following:

  • KBr
  • KBr 2NH4OH
  • KBr 2NH4OH2HNO2

<h3>What is neutralisation reaction?</h3>

Neutralisation reaction is defined as the type of reaction that leads to the formation of salt and water when an acid and a base reacts.

From the reactions given the missing components are replaced as follows:

  • HBr + KOH --> KBr + H2O

  • H2SO4 + 2NH4OH --> (NH4)2SO4 + 2H2O

  • 2HNO3 + Mg(OH)2 --> Mg(NO3)2 + 2H2O

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2C2H2(g)+5O2(g)=4CO2(g)+2H2O(g)
balandron [24]

The volume of ethyne, C₂H₂ required to produce 12 moles of CO₂ assuming the reaction is at STP is 134.4 L

<h3>Balanced equation</h3>

2C₂H₂(g) + 5O₂(g) --> 4CO₂(g) + 2H₂O(g)

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

<h3>How to determine the mole of C₂H₂ needed to produce 12 moles of CO₂</h3>

From the balanced equation above,

4 moles of CO₂ were produced by 2 moles of C₂H₂

Therefore,

12 moles of CO₂ will be produce by = (12 × 2) / 4 = 6 moles of C₂H₂

<h3>How to determine the volume (in L) of C₂H₂ needed at STP</h3>

At standard temperature and pressure (STP),

1 mole of C₂H₂ = 22.4 L

Therefore,

6 moles of C₂H₂ = 6 × 22.4

6 moles of C₂H₂ = 134.4 L

Thus, we can conclude that the volume of C₂H₂ needed for the reaction at STP is 134.4 L

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