Answer:
<em>Johnny had </em><em>5</em><em> items and Bobby had </em><em>13</em><em> items.</em>
Step-by-step explanation:
Let us assume that Johnny has x items and Bobby has y items in their list.
Bobby had 3 more than twice as many items on it than Johnny. So,
----------1
Johnny asked for 8 fewer items than bobby. So,
-----------2
Putting the value of x from equation 2 in equation 1, we get
Putting the value of y in equation 2,
So, Johnny had 5 items and Bobby had 13 items.
4/6 5/10 7/12. Hope this helped! :)
Using statistical concepts, it is found that:
- 2 modes would be expected for the distribution.
- The distribution would be symmetric.
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- Heights are traditionally normally distributed, which is a symmetric distribution.
- Second-grade students are considerably shorter than college students, so there would be two modes.
- Both distributions, for the height of second grade and of college students, are normal, which is symmetric, thus the combined distribution will also be symmetric.
A similar problem is given at brainly.com/question/13460485
Answer:
m∠Z1 = 93°
Step-by-step explanation:
Vertical Angles are the angles opposite each other when two lines cross.
They are congruent (the same as each other).
Therefore, m∠Z1 = m∠Z2, so if m∠Z2 = 93° then m∠Z1 = 93°
Since the two lines are parallel and it is cut by a transversal,
75+X+5=180
=>80+X=180
=>X=180-80
==>X=100
Hope this helps u...!!!!!
