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3 years ago

13

Can anyone answer this? x+1<5

1 answer:

Sliva [168]3 years ago

5 0

X + 1 < 5
x < 5 - 1
x < 4

u basically solve it like equations except for one important rule....with inequalities, when u multiply/divide by a negative number, the inequality sign changes directions. But we didn't have to deal with that rule in this particular problem

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(1+v)(v-7) i need help to solve this question

kramer

(1 + v)(v - 7)

1*(v - 7) + v(v - 7)

1*v - 1*7 + v*v - v*7

v - 7 + v² - 7v

v² - 7v + v - 7

v² - 6v - 7

I hope this helps.

4 0

3 years ago

3 - (2x - 5) < -4(x + 2)

DIA [1.3K]

Answer:

x < -8

Step-by-step explanation:

3 - (2x - 5) < -4(x + 2)

-2x + 8 < -4x - 8

-2x < -4x - 16

2x < -16

x < -8

Best of Luck!

7 0

3 years ago

Can Someone Please Help Me With This Question. I'll post a picture of the question

Vedmedyk [2.9K]

Answer:

$y-7=3(x-9)$

Step-by-step explanation:

The form of equation of line given in the problem is the point-slope form of a line. That is given by:

$y-y_1=m(x-x_1)$

We need $y_1$ and m (denoted by boxes)

$y_1$ is the y coordinate of the first set of points.

The first coordinate pair is (9,7), so $y_1$ would be 7

$y_1=7$

Now, the slope (m).

It has formula

$m=\frac{y_2-y_1}{x_2-x_1}$

So, x_1 = 9

y_1 = 7

x_2 = 4

y_2 = -8

Substituting, we get the slope to be:

$m=\frac{y_2-y_1}{x_2-x_1}\\m=\frac{-8-7}{4-9}\\m=\frac{-15}{-5}\\m=3$

Hence, the equation of the line in point-slope is:

$y-7=3(x-9)$

5 0

2 years ago

If the line t is a transversal of lines I and m, NAME THE SPECIAL ANGLE PAIR RELATIONSHIP of the given angle pairs.

Hunter-Best [27]

Answer:

a. <1 and <3

Step-by-step explanation:

8 0

3 years ago

Y-4x=9 in standard form

11111nata11111 [884]

Answer: y - 4x = 9 <em>in standard form is</em> -y + 4x = -9

4 0

3 years ago