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4 years ago

For an object to move, a(n) _______ force must be applied. Question 1 options: Balanced Unbalanced

Physics

1 answer:

Dominik [7]4 years ago

6 0

Answer:

Unbalenced

Explanation:

when balenced forces are applied to an object there is no motion. When you apply unbalenced force the object you are applying the force to will move in the opposite direction of the force.

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4 years ago

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An air-track glider attached to a spring oscillates between the 13.0 cm mark and the 63.0 cm mark on the track. The glider compl

LuckyWell [14K]

Answer:

(A) = 2.13 s

(B) = 0.47 Hz

(C) = 0.25 m

(D) = 0.74 m/s

Explanation:

number of oscillations (n) = 15

time (t) = 32 secs

start point (L1) = 13 cm = 0.13 m

End point (L2) = 63 cm = 0.63 m

(A) period = time / number of oscillation

= 32 / 15 = 2.13 s

(B) frequency = 1 / period

= 1 / 2.13 = 0.47 Hz

= 0.5 ( 0.63 - 0.13 )

= 0.25 m

(D) max speed = (2π / T) x A

= (2π / 2.13) x 0.25

= 0.74 m/s

6 0

3 years ago

Suppose a two-level system is in a bath with temperature 247 K. The energy difference between the two states is 1.1 × 10-21 J. W

Alik [6]

Answer:

The probability of higher energy state is 0.4200.

Explanation:

Given that,

Temperature = 247 K

Energy difference between two states $E_{2}-E_{1}=1.1\times10^{-21}\ J$

We need to calculate the probability of higher energy state

Probability of $E_{1}= e^{-\beta E_{1}}$

Probability of $E_{2}= e^{-\beta E_{2}}$

The total probability is

$e^{-\beta E_{1}}+e^{-\beta E_{1}}=1$

Here, E₁ = lower energy state

E₂ = higher energy state

Put the value of E₁ in to the formula

$e^{-\beta(E_{2}-1.1\times10^{-21})}+e^{-\beta E_{1}}=1$

$e^{-\beta E_{2}}(e^{\beta 1.1\times10^{-21}}+1)=1$

$e^{\beta E_{2}}=\dfrac{1}{1+e^{\dfrac{1.1\times10^{-21}}{KT}}}$

Here, $\beta=\dfrac{1}{KT}$

Put the value into the formula

$e^{\beta E_{2}}=\dfrac{1}{1+e^{\dfrac{1.1\times10^{-21}}{1.380\times10^{-23}\times247}}}$

$e^{\beta E_{2}}=0.4200$

Hence, The probability of higher energy state is 0.4200.

4 0

3 years ago