Answer:
31.75 m/s
Explanation:
h = 41.7 m
Let the initial velocity of the second stone is u
Let the time taken to reach to the bottom by the first stone is t then the time taken by the second stone to reach the ground is t - 1.8.
For first stone:
Use second equation of motion
Here, u = 0, g = 9.8 m/s^2 and t be the time and h = 41.7
So, 41.7= 0 + 0.5 x 9.8 x t^2
41.7 = 4.9 t^2
t = 2.92 s ..... (1)
For second stone:
Use second equation of motion
Here, g = 9.8 m/s^2 and time taken is t - 1.8 = 2.92 - 1.8 = 1.12 s, h = 41.7 m and u be the initial velocity
.... (2)
By equation the equation (1) and (2), we get
u = 31.75 m/s
<span>Anger is to angry as fire is to blazing. </span>
Answer:
The curl is 
Explanation:
Given the vector function
We can calculate the curl using the definition
Thus for the exercise we will have
So we will get
Working with the partial derivatives we get the curl
Answer:
= 33.33 cm
Explanation:
Given:
When mass, 
=21 kg
distance travelled is 
= 140 cm
When mass, 
=5 kg
distance travelled is = ?
Hooke's law state that within elastic limit, when an external force is applied to a body, the body gets deformed and when the force is released the gets back to its original form.
Therefore according to the question,
= 33.33 cm
Distance travelled is 33.33 cm when mass is 5 kg.
