3x + 5 = 23
5 more than(addition) 3 times(multiplication) a variable(x) is(equals) 23
(you add 5 to 3x)
If you need to solve for "x", you need to isolate/get the variable "x" by itself in the equation:
3x + 5 = 23 Subtract 5 on both sides
3x + 5 - 5 = 23 - 5
3x = 18 Divide 3 on both sides to get "x" by itself
x = 6
Answer:
g(x) is shifted 6 units to the left
Step-by-step explanation:
Lets try to simplify g(x) since has a few extra terms:
g(x)= 3x+12-6=3x+6
Now it is easier to compare the two functions.
We can tell that they both have the same slope, both differs on a extra term
This term tell us that the g(x) is shifted to the left (it is positive 6)
Another approach to the solution is to plot the two functions together by obtaining the crossing points with the 'y' axis and with the 'x' axis
the result is shown in the attached picture
a) You are told the function is quadratic, so you can write cost (c) in terms of speed (s) as
... c = k·s² + m·s + n
Filling in the given values gives three equations in k, m, and n.
Subtracting each equation from the one after gives
Subtracting the first of these equations from the second gives
Using the next previous equation, we can find m.
Then from the first equation
[tex]28=100\cdot 0.01+10\cdot (-1)+n\\\\n=37[tex]
There are a variety of other ways the equation can be found or the system of equations solved. Any way you do it, you should end with
... c = 0.01s² - s + 37
b) At 150 kph, the cost is predicted to be
... c = 0.01·150² -150 +37 = 112 . . . cents/km
c) The graph shows you need to maintain speed between 40 and 60 kph to keep cost at or below 13 cents/km.
d) The graph has a minimum at 12 cents per km. This model predicts it is not possible to spend only 10 cents per km.
