It is 2 lol also use a calculator it’s wayyy easier this is like the easiest equation every
11c-8
11c is the product of both 11 and c, and the 8 less than the product is shown with -8
Answer:
It will cost Mr. Smith $68 to make his suit.
Step-by-step explanation:
Since the charge $12 per hour, and it takes 4 hours to make the suit, then we need to multiply 12 by 4.
12 × 4 = 48
Now we need to add the flat rate since that is the initial charge for service.
48 + 20 = 68
This means it will cost Mr. Smith a total of $68 for his suit.
Answer:
Step-by-step explanation:
Mixture problems are really easy because the table never varies from one problem to another and they don't have a lot of variations in them like motion problems do. The table for us will look like this, using T for Terraza coffee and K for Kona:
#lbs x $/lb = Total
T
K
Mix
Now we just have to fill this table in using the info given. We are told that T coffee is $9 per pound, and that K coffee is $13.50 per pound, so we will fill that in first:
#lbs x $/lb = Total
T 9
K 13.50
Mix
Next we are told that the mix is to be 50 pounds that will sell for $9.54 per pound
#lbs x $/lb = Total
T 9
K 13.50
Mix 50 9.54
Now the last thing we have to have to fill in this table is what goes in the first column in rows 1 and 2. If we need a mix of 50 pounds of both coffees and we don't know how many pounds of each to use, then under T we have x and under K we have 50 - x. Notice along the top we have that the method to use to solve this problem is to multiply the #lbs by the cost per pound, and that is equal to the Total. So we'll do that too:
#lbs x $/lb = Total
T x x 9 = 9x
K 50 - x x 13.50 = 675 - 13.50x
Mix 50 x 9.54 = 477
The last column is the one we focus on. We add the total of T to the total of K and set it equal to the total Mix:
9x + 675 - 13.5x = 477 and
-4.5x = -198 so
x = 44 pounds. This means that the distributor needs to mix 44 pounds of T coffee with 6 pounds of K coffee to get the mix he wants and to sell that mix for $9.54 per pound.
Area is equal to length times width. The perimeter (the amount of rope) has to equal twice the length added to twice the width so we're left with:
A = l * w
200 = 2l + 2w
solve for either l or w
l = 100 - w
plug into the area equation to get one equation with two variables
A = w(100 - w)
A = -w^2 + 100w
take the derivative
A' = -2w + 100
set the derivative equal to zero
0 = -2w + 100
2w = 100
w = 50
This is the width that maximizes the area
with a width of 50, the length must also be 50 to have a perimeter of 200
therefore, they can rope up to 50 * 50 = 2500 ft^2
