The result of simplifying the expression (x²/x⁻¹¹)¹/₃ using the exponent rules is ![\sqrt[3]{}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%7D)
(x¹³)
To solve this exercise we have to resolve algebraic operations following the exponent rules.
(x²/x⁻¹¹)¹/₃
Using the quotient rule that indicates that: the exponent result will be the subtraction of these exponents, we have:
(x⁽²⁻⁽⁻¹¹⁾)¹/₃
(x⁽²⁺¹¹⁾)¹/₃
(x¹³)¹/₃
Using the power of a power rule that indicates that: the exponent result will be the multiplication of these powers, we have:
x⁽¹³*¹/₃⁾
x⁽¹³/₃⁾
As we have a fractional exponent, you must convert the exponent to root:
(x¹³)
<h3>What is an exponent?</h3>
In mathematics an exponent is the number of time that a number, called (base) is multiplied by itself. It is also called, power or index.
Example: 3² = 3*3 = 9
Learn more about exponent at: brainly.com/question/847241
#SPJ4
I hope this helps you
12x/2+24/2
6x+12
-6 ( -x-2)
Answer:
60
Step-by-step explanation:
you multiply 150*4 then divide that by 10 and that's your answer
Answer: 112 meters
Step-by-step explanation:
Hi, to answer this question we have to apply the next formula:
- Volume of a cylinder (V) : π x radius ² x height
Replacing with the values given :
842,411 = π x r ² x 85
Solving for r:
842,411 / (π x 85) = r²
3,154.67 = r²
√3,154.67 = r
56.16 m = r
Finally, we have to multiply the radius by 2 to obtain the diameter:
56.16 x 2 = 112 meters
Feel free to ask for more if needed or if you did not understand something
Domain is the entire span left to right (on the x-axis) that the graph is on. Since the graph goes from x=-4 and ends at x=4, the domain would be from -4 to 4. The circle at -4 is open, so it does not include the point at -4, just everything leading up to it. So, the domain would be
The range is similar, it is the entire span that the graph goes up and down (on the y-axis). The graph starts at the bottom at y=-2, and ends at y=5. The bottom point (4,-2) is closed, so the graph includes that point, and the top point (-4,5) is open and doesn't include the point. Therefore, the range would be
