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dusya [7]
3 years ago
13

A student mixes two solutions together. One is believed to be HI, the other is believed to be HNO3. A precipitate forms. Believi

ng the results may be in error the student repeats the process twice in separate wells. After repeating the trial there was no observed precipitate. What is the most likely reason for the initial precipitate result?
Chemistry
1 answer:
4vir4ik [10]3 years ago
5 0

Answer:

The presence of <em>silver nitrate impurities</em> is the most probable cause for the initial precipitate result.

Explanation:

In test for halide ions, silver nitrate AgNO_{3} is used to test for the presence of soluble halide ions. The presence of AgNO_{3} in the reaction mixture (possibly the HNO3) gave the semblance of test for chlorides, allowing for formation of precipitation in the initial experiment.

This error could have been caused by handling of reagents and used laboratory apparatus during the initial reaction.

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Which of th following is an example of how scientist might use a model?
Gemiola [76]
C. marbles placed inside hollow sphere
8 0
3 years ago
One crystalline form of silica (SiO2) has a cubic unit cell, and from X-ray diffraction data it is known that the cell edge leng
tigry1 [53]

Answer:

There are 8Si atoms and 16 O atoms per unit cell

Explanation:

From the question we are told that:

Edge length l=0.700nm=>0.7*10^9nm

Density \rho=2.32g/cm^3

Generally the equation for Volume is mathematically given by

V=l^3

V=(0.7*10^9)m^3

V=3,43*10^-{22}cm

Where

Molar mass of  (SiO2) for one formula unit

M=28+32

M=60g/mol

Therefore

Density of Si per unit length is

\rho_{si}=\frac{9.96*10^{23}}{3.43*10^22}

\rho=0.29

Molar mass of  (SiO2) for one formula unit

M=28+32

M=60g/mol

Therefore

There are 8Si atoms and 16 O atoms per unit cell

6 0
3 years ago
Calculate the molar solubility of silver(i) bromate with ksp = 5. 5×10-5. also, convert the molar solubility to the solubility.
Sindrei [870]

The molar solubility is 7.4×10^{-3} M and the solubility is  7.4×10^{-3} g/L .

Calculation ,

The dissociation of silver bromide is given as ,

AgBr → Ag ^{+} + Br^{-}

S  

 -          S        S        

Ksp =  [Ag ^{+} ] [ Br^{-} ]  =  [S] [ S ] = S^{2}

S = √ Ksp = √ 5. 5×10^{-5} = 7.4×10^{-3}

The solubility =7.4×10^{-3} g/L

The molar solubility is the solubility of one mole of the substance.

Since ,  one mole of AgBr is dissociates and form one mole of each  Ag ^{+} and Br^{-} ion . So, solubility is equal to molar solubility but unit is different.

Molar solubility = 7.4×10^{-3} mol/L = 7.4×10^{-3} M

To learn more about molar solubility ,

brainly.com/question/16243859

#SPJ4

7 0
1 year ago
In principle, the equilibrium in the dehydration of an alcohol could be shifted to the right be removal of water. Why is this ta
Trava [24]

Answer:

See explanation

Explanation:

In this case, we have to remember that if we want to remove water from the reaction vessel we have to heat the vessel. So, we can convert the liquid water into <u>gas water</u> and we can remove it from the vessel. In this case, the products of dehydration for both molecules are <u>(E)-4-methylpent-2-ene</u> and <u>cyclohexene</u> with boiling points of <u>59.2 ºC</u> and <u>89 ºC</u> respectively. The boiling point of water is <u>100 ºC</u>, therefore if we heat the vessel the products and water would leave the system, and the products would be lost.

See figure 1

I hope it helps!

3 0
3 years ago
Please help!!!!!!!!!!!!!!!
svlad2 [7]
The 2nd one is the right answer

Hope this helped
3 0
3 years ago
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