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dusya [7]
2 years ago
13

A student mixes two solutions together. One is believed to be HI, the other is believed to be HNO3. A precipitate forms. Believi

ng the results may be in error the student repeats the process twice in separate wells. After repeating the trial there was no observed precipitate. What is the most likely reason for the initial precipitate result?
Chemistry
1 answer:
4vir4ik [10]2 years ago
5 0

Answer:

The presence of <em>silver nitrate impurities</em> is the most probable cause for the initial precipitate result.

Explanation:

In test for halide ions, silver nitrate AgNO_{3} is used to test for the presence of soluble halide ions. The presence of AgNO_{3} in the reaction mixture (possibly the HNO3) gave the semblance of test for chlorides, allowing for formation of precipitation in the initial experiment.

This error could have been caused by handling of reagents and used laboratory apparatus during the initial reaction.

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3 years ago
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Each of the following names is wrong. Draw structures based on them, and correct the names:(b) 1,1,1-trimethylheptane
devlian [24]

The correct IUPAC name of 1,1,1-trimethylheptane is 2,2-dimethyloctane.

<h3>IUPAC NAME:</h3>

It is systematic way of nomenclature of organic compounds.

It is based on the position of functional groups, preference of the functional group, long or short chain of carbon, preference of double bond, single and triple bond, branching of carbon chain, etc.

The given compound is 1,1,1-trimethylheptane.

The given name is wrong according to IUPAC name because the numbering of carbon atom should be done in that way in which the carbon atom chain is largest.

Here, in this case the numbering is done from right side. Thus the largest carbon chain have 8 carbon atom.

If the numbering is done according to the question, number of carbon atom in straight chain is 7.

Thus, we concluded that the Correct IUPAC name of 1,1,1-trimethylheptane is 2,2-dimethyloctane.

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5 0
1 year ago
A group 2 metal carbonate has a mass of 84 g/mol. Identify the group 2 metal X using its chemical formula.
zepelin [54]

Answer:

Magnesium

0.003mole

Explanation:

The problem here entails we find the metal in the carbonate.

 For group 2 member, let the metal  = X;

 The carbonate is XCO₃;

 If we sum the atomic mass of the elements in the metal carbonate, we should arrive at 84g/mol

 Atomic mass of C = 12g/mol

                            O  = 16g/mol

 Atomic mass of X + 12 + 3(16)  = 84

  Atomic mass of X  = 84 - 60  = 24g/mol

The element with atomic mass of 24g is Magnesium

B.

Number of moles in 0.3g of CaCO₃:

     Molar mass of CaCO₃   = 40 + 12 + 3(16)  = 100g/mol

 Number of moles = \frac{mass}{molar mass}  

 Number of moles  = \frac{0.3}{100}   = 0.003mole

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