A student mixes two solutions together. One is believed to be HI, the other is believed to be HNO3. A precipitate forms. Believi
1 answer:
Answer:
The presence of <em>silver nitrate impurities</em> is the most probable cause for the initial precipitate result.
Explanation:
In test for halide ions, silver nitrate is used to test for the presence of soluble halide ions. The presence of
in the reaction mixture (possibly the HNO3) gave the semblance of test for chlorides, allowing for formation of precipitation in the initial experiment.
This error could have been caused by handling of reagents and used laboratory apparatus during the initial reaction.
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Answer:
412 g Cl₂
General Formulas and Concepts:
<u>Atomic Structure</u>
- Reading a Periodic Table
- Moles
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
[Given] 3.50 × 10²⁴ molecules Cl₂
[Solve] grams Cl₂
<u>Step 2: Identify Conversions</u>
Avogadro's Number
[PT] Molar Mass of Cl - 35.45 g/mol
Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol
<u>Step 3: Convert</u>
- [DA] Set up:
- [DA] Divide/Multiply [Cancel out units]:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
412.072 g Cl₂ ≈ 412 g Cl₂