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alexira [117]
3 years ago
11

Metric equivalent to 4 tbsp

Chemistry
1 answer:
yulyashka [42]3 years ago
3 0
2 fl oz is the metric equivalent to 4 tbsp
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Which of the following can be considered evidence?
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3 years ago
Do valence electrons show a repeating or periodic pattern
PolarNik [594]

Yes

Explanation:

Valence electrons on the periodic table of elements shows a repeating or periodic pattern. There is a noticeable pattern that can be deduced from the valence electrons in the orbitals of atoms.

    Valence electrons are the electrons in the outermost shell of an element

The periodic table arranges elements based on their atomic numbers. This number denotes the number of protons or electrons an atom contains.

  • The table is divided into groups which are the vertical columns into which elements are classified.
  • The horizontal rows are called periods.
  • A period begins with one valence electron and ends with an atom having complete outer shell structure of an inert gas.
  • Down a group the valence electron is the same. The group number denotes the number of valence electrons in a group. Group 1 has just one valence electron in their outermost shell.

Learn more:

Valence electrons brainly.com/question/12580690

Periodic table brainly.com/question/2014634

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8 0
3 years ago
How do particles in soild move?
Harman [31]
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7 0
3 years ago
Read 2 more answers
Which compound contains both sigma and pi bonds? HCCl3 H2CO H2S HBr.
Aliun [14]

The compound that contains both sigma and pi bonds has been \rm \bold{H_2CO}. Thus, option B is correct.

The compounds have been resulted by the sharing of the valence electrons between atoms, for the completion of octet of each elements.

The bonds can be saturated with the presence of only sigma bond. The unsaturated bonds has presence of pi bonds as well. The bond with one pi and one sigma has been a double bond, while 1 sigma and 2 pi has been a triple bond.

The bonds present in the following structures has been:

\rm HCCl_3=4\;\sigma\;bonds\\H_2CO=2\;\sigma,\;1\;\pi\;bond\\H_2S=2\;\sigma\;bonds\\HBr\;=1\;\sigma\;bond

The compound with the presence of both sigma and pi bonds has been \rm \bold{H_2CO}. Thus, option B is correct.

For more information about the sigma and pi bonds, refer to the link:

brainly.com/question/14018074

6 0
2 years ago
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