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nexus9112 [7]
3 years ago
14

QUESTION 17

Chemistry
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

72.3%

Explanation:

The following data were obtained from the question:

Theoretical yield of MgO = 3.43 g

Actual yield of MgO = 2.48g

Percentage yield of MgO =.?

Percentage yield of a reaction can simply be obtained by dividing the actual yield by the theoretical yield multiplied by 100. This is illustrated below:

Percentage yield = Actual yield /Theoretical yield × 100

Thus, we can obtain the percentage yield of MgO as follow:

Theoretical yield of MgO = 3.43 g

Actual yield of MgO = 2.48g

Percentage yield of MgO =.? Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 2.48/3.43 × 100

Percentage yield = 72.3%

Therefore, the percentage yield of MgO is 72.3%.

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Explanation:

Expression for the v_{rms} speed is as follows.

            v_{rms} = \sqrt{\frac{3kT}{M}}

where,   v_{rms} = root mean square speed

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                    T = temperature

                    M = molecular mass

As the molecular weight of oxygen is 0.031 kg/mol and R = 8.314 J/mol K. Hence, we will calculate the value of v_{rms} as follows.

               v_{rms} = \sqrt{\frac{3kT}{M}}

                            = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.02 K}{0.031 kg/mol}}

                            = 498.5 m/s

Hence, v_{rms} for oxygen atom is 498.5 m/s.

For nitrogen atom, the molecular weight is 0.028 kg/mol. Hence, we will calculate its v_{rms} speed as follows.

                v_{rms} = \sqrt{\frac{3kT}{M}}

                              = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.92 K}{0.028 kg/mol}}

                              = 524.5 m/s

Therefore, v_{rms} speed for nitrogen is 524.5 m/s.

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Based on the activity series of metal, which reaction with water will not happen?
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Answer:

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Answer:

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