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nexus9112 [7]
3 years ago
14

QUESTION 17

Chemistry
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

72.3%

Explanation:

The following data were obtained from the question:

Theoretical yield of MgO = 3.43 g

Actual yield of MgO = 2.48g

Percentage yield of MgO =.?

Percentage yield of a reaction can simply be obtained by dividing the actual yield by the theoretical yield multiplied by 100. This is illustrated below:

Percentage yield = Actual yield /Theoretical yield × 100

Thus, we can obtain the percentage yield of MgO as follow:

Theoretical yield of MgO = 3.43 g

Actual yield of MgO = 2.48g

Percentage yield of MgO =.? Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 2.48/3.43 × 100

Percentage yield = 72.3%

Therefore, the percentage yield of MgO is 72.3%.

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6 0
2 years ago
The equation shows one mole of ethanol fuel being burned in oxygen. Convert the energy released into its equivalent mass. C2H5OH
lana [24]

Answer:

47.9 g of ethanol

Explanation:

Combustion is a chemical reaction in which a substance reacts with oxygen to produce heat and light. Combustion reactions have been very useful as a source of energy. Ethanol is now burnt for energy purposes as a fuel. Ethanol has even been proposed as a possible alternative to fossil fuels.

Since 1 mole of ethanol when combusted releases 1367 kJ/mol of energy

x moles of ethanol releases 1418 kJ/mol.

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Mass of ethanol= 47.9 g of ethanol

7 0
3 years ago
PLEASE HELP ITS DUE TODAY!
Yuri [45]

Answer:

At one atmosphere and twenty-five degrees Celsius, could you turn it into a liquid by cooling it down? Um, and the key here is that the triple point eyes that minus fifty six point six degrees Celsius and it's at five point eleven ATMs. So at one atmospheric pressure, there's no way that you're ever going to reach the liquid days. So the first part of this question is the answer The answer to the first part of a question is no. How could you instead make the liquid at twenty-five degrees Celsius? Well, the critical point is at thirty-one point one degrees Celsius. So you know, if you're twenty-five, if you increase the pressure instead, you will briefly by it, be able to form a liquid. And if you continue Teo, you know, increase the pressure eventually form a salad, so increasing the pressure is the second part. If you increase the pressure of co two thirty-seven degrees Celsius, will you ever liquefy? No. Because then, if you're above thirty-one point one degrees Celsius in temperature. You'LL never be able to actually form the liquid. Instead, you'LL only is able Teo obtain supercritical co too, which is really cool thing. You know, they used supercritical sio tu tio decaffeinated coffee without, you know, adding a solvent that you'LL be able to taste, which is really cool. But no, you can't liquefy so two above thirty-one degrees Celsius or below five-point eleven atmospheric pressures anyway, that's how I answer this question. Hope this helped :)

5 0
2 years ago
How to determine reaction order in reactant?
Artyom0805 [142]
In order to determine, Order of reaction, we have to add all the exponents written in the Chemical form, on the Reactant species.

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8 0
3 years ago
A nugget of GOLD has a mass 9.66 gram and a volume of 0.5 cm3, It's density is<br>grams/cm3 *​
dalvyx [7]

Answer:

P=19.32g/cm³

Explanation:

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4 0
3 years ago
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