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Levart [38]
4 years ago
14

What is mandrake tuber

Chemistry
1 answer:
Rudiy274 years ago
4 0
It's botanical name would be Mandragora officianarum, and it has a humanoid shape. Its a murderous plant that grows from blood that grows in Mediterranean.
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What is the formula unit for a compound made from Pb4+ and oxygen?
Volgvan

Maybe Lead and Oxygen?

8 0
4 years ago
Read 2 more answers
Explain why silicon carbide has a very high melting point​
Allushta [10]

Answer:

Silicon has a very high melting point due to its giant covalent structure; a lot of energy is needed to break the strong covalent bonds throughout the structure.

Explanation:

4 0
2 years ago
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A solution used to chlorinate a home swimming pool contains 7% chlorine by mass. An ideal chlorine level for the pool is one par
deff fn [24]

Answer:

Volume of chlorine = 61.943 mL

Explanation:

Given:

Volume of the water in the Pool = 18,000 gal

also,

1 gal = 3785.412 mL

thus,

Volume of water in pool = 18,000 × 3785.412 = 68,137,470 mL

Density of water = 1.00 g/mL

Therefore,

The mass of water in the pool = Volume × Density

or

The mass of water in the pool = 68,137,470 mL × 1.00 g/mL = 68,137,470 g

in terms of million = \frac{\textup{68,137,470}}{\textup{ 1,000,000}}

or

= 68.13747 g

also,

1 g of chlorine is present per million grams of water

thus,

chlorine present is 68.13747 g

Now,

volume = \frac{\textup{Mass}}{\textup{Density}}

or

Volume of chlorine = \frac{\textup{68.13747 g}}{\textup{1.10 g/mL}}

or

Volume of chlorine = 61.943 mL

3 0
4 years ago
Sr(OH)2 will dissociate into what ions with what charge
Vinil7 [7]

Answer : Sn(OH)_2 will dissociate into strontium ion, Sr^{2+} with a (+2) charge and hydroxide ion, OH^- with a (-1) charge.

Explanation :

As we know that when strontium hydroxide, Sn(OH)_2 dissociates then it gives strontium ion, Sr^{2+} and hydroxide ion, OH^-.

The dissociation reaction will be:

Sr(OH)_2\rightarrow Sr^{2+}+2OH^-

Sn(OH)_2 will dissociate into strontium ion, Sr^{2+} with a (+2) charge and hydroxide ion, OH^- with a (-1) charge.

8 0
4 years ago
A gas that was cooled to 200 Kelvin has a volume of 65.8 L. If its initial volume was 132.4 L, what was its initial temperature?
Mandarinka [93]

Answer:

Initial temperature, T1 = 99.4 Kelvin

Explanation:

<u>Given the following data;</u>

  • Initial volume, V1 = 65.8 Litres
  • Final temperature, T2 = 200 Kelvin
  • Final volume, V2 = 132.4 Litres

To find the initial temperature (T1), we would use Charles' law;

Charles states that when the pressure of an ideal gas is kept constant, the volume of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Charles' law is given by the formula;

\frac {V}{T} = K

\frac {V_{1}}{T_{1}} = \frac {V_{2}}{T_{2}}

Making T1 as the subject formula, we have;

T_{1} = \frac {V_{1}T_{2}}{V_{2}}

Substituting the values into the formula, we have;

T_{1} = \frac {65.8 * 200}{132.4}

T_{1} = \frac {13160}{132.4}

<em>Initial temperature, T1 = 99.4 Kelvin</em>

6 0
3 years ago
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