We use the kinematics equation:
Vf = Vi + a*t
8 = 0 + 3.6 * t
t=2.222s to reach 8.0 m/s
At that time the train has moved
4.5 m/s * 2.222s = 9.999 m
He travelled (another kinematics equation)
Vf^2 = Vi^2 + (2*a*d)
(8.0)^2 = (0)^2 + (2 * 3.6 * d)
d=8.888 m
The train is 9.999m, the fugitive is 8.888m,
He still needs to travel
9.999-8.888= 1.111m
He needs to cover the rest of the distance in a smaller amount of time, however hes at his maximum velocity, so...
8m/s(man) - 4.5m/s(train) = 3.5 m/s more
(1.111m) / (3.5m/s) = .317seconds more to reach the train
So if it takes 2.222 seconds to approach the train at 8.888m, it should take
2.222 + .317 =2.529 seconds to reach the train completely
Last but not least is to figure out the total distance traveled in that time frame:
(Trains velocity) * (total time)
(4.5m/s)*(2.529s)=11.3805m
Answer:
Explanation:
The marble released through the trap door inside the elevator going upward at a speed vo would have an upward velocity of vo, but begins to experience a downward acceleration g = 9.81m/s^2. This is essentially same as throwing the marble up at a speed of vo. We can solve for the greatest height using the law of energy conservation.
When the marble is traveling up, its potential energy is converted to kinetic energy:
where m is the marble mass and h is the vertical distance traveled from the releasing point to the maximum height.
We can divide both sides by m
This is only partial of the height from the ground. To find the total height we need to add the height from the ground to the release point, which is the distance traveled by the elevator within time t = 2.35s at speed vo
Plug in the value for vo and we can calculate the maximum height
As you were holding the block down and in place, the spring exerted an upward force that balanced the downward push by your hand and its own weight. So this restoring force has a magnitude of <em>R</em> such that
<em>R</em> - 50 N - (3 kg) <em>g</em> = 0 => <em>R</em> = 79.4 N
As soon as you remove your hand, the block has acceleration <em>a</em> such that, by Newton's second law,
<em>R</em> - (3 kg) <em>g</em> = (3 kg) <em>a</em> => <em>a</em> = (79.4 N - (3 kg) <em>g</em>) / (3 kg) ≈ 16.7 m/s^2
pointing upward.
Answer:
<em>If the amount of water in the glass is close to brimming, then the pitch will ring as high-toned. </em>
Hope it helped :)
