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attashe74 [19]
3 years ago
13

How does having a sharp pointed beak limit what foods a bird can eat?

Physics
1 answer:
liraira [26]3 years ago
4 0

Answer:

The shape of a bird's beak is a clue to its main source of food. The shape of a bird's beak is designed for eating particular types of food such as: seeds, fruit, insects, nectar, fish, or small mammals. Bird beaks have adapted over time to help birds find food within their habitat which allows them to survive. The beak, bill, and/or rostrum is an external anatomical structure found mostly in birds, but also in non-avian dinosaurs and some mammals. A beak is used for eating and for preening, manipulating objects, killing prey, fighting, probing for food, courtship and feeding young.

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Find the area of the part of the plane 5x 3y z = 15 that lies in the first octant.
Lunna [17]

This part of the plane lies above a triangle with boundaries x=0 and y=0 along the coordinate axes, as well as the line

z=0 \implies 5x + 3y = 15 \implies y = \dfrac{15 - 5x}3

When y=0, we have 15-5x=0\implies x=3. So this triangle is the set

T = \left\{(x,y)\in\Bbb R^2 ~:~ 0\le x\le3 \text{ and } 0\le y\le\dfrac{15-5x}3\right\}

Also, when x=0, we have y=\frac{15}3=5. So the triangle has length 3 and width 5, hence area 1/2•3•5 = 15/2.

Let z=f(x,y) = 15 - 5x - 3y. Then the area of the plane over T is

\displaystyle \iint_T dA = \iint_T \sqrt{1 + \left(\frac{\partial f}{\partial x}\right)^2 + \left(\frac{\partial f}{\partial y}\right)^2} \, dx \, dy

We have

\dfrac{\partial f}{\partial x} = -5 \implies \left(\dfrac{\partial f}{\partial x}\right)^2 = 25

\dfrac{\partial f}{\partial y} = -3 \implies \left(\dfrac{\partial f}{\partial y}\right)^2 = 9

\implies\displaystyle \iint_T dA = \sqrt{35} \iint_T dx\,dy = \boxed{\frac{15\sqrt{35}}2}

since the integral

\displaystyle \iint_TdA

is exactly the area of T, 15/2.

8 0
1 year ago
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barxatty [35]

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7 0
2 years ago
A car is at velocity of 20 km/h. If the car traveled 120 km in 3 hours at constant acceleration, what is its final velocity?
dedylja [7]
The velocity is dueuueue. 100
8 0
3 years ago
If a typical current density (current per unit cross-sectional area) in the cell membrane is 5 mA/cm2 when the voltage across th
Readme [11.4K]

Answer:

<u>note: </u>

<u>solution is attached in word form due to error in mathematical equation. furthermore i also attach Screenshot of solution in word due to different version of MS Office please find the attachment </u>

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4 0
3 years ago
1. A kangaroo hops 84 m to the east in 7 seconds.
DENIUS [597]

Explanation:

Given parameters:

Distance hopped  = 84m

Displacement  = 84m due east

Time  = 7s

Unknown:

Speed of kangaroo  = ?

Velocity of kangaroo  = ?

Solution:

To solve this problem,

    Speed  = \frac{distance}{time }   = \frac{84}{7}  = 12m/s

  Velocity  = \frac{displacement}{time}   = \frac{84}{7}   = 12m/s due east

3 0
3 years ago
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