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skad [1K]
3 years ago
10

Question 6 (10 points)

Physics
1 answer:
horsena [70]3 years ago
7 0

Answer:

a= g = - 9.81 m/s2.

The following equations will be helpful:

a = (vf - vo)/t d = vot + 1/2 at2 vf2 = vo2 + 2ad

When you substitute the specific acceleration due to gravity (g), the equations are as follows:

g = (vf - vo)/t d = vot + 1/2 gt2 vf2 = vo2 + 2gd

If the object is dropped from rest, the initial velocity ("vi") is zero. This further simplifies the equations to these:

g = vf /t d = 1/2 gt2 vf2 = 2gd

The sign convention that we will use for direction is this: "down" is the negative direction. If you are given a velocity such as -5.0 m/s, we will assume that the direction of the velocity vector is down. Also if you are told that an object falls with a velocity of 5.0 m/s, you would substitute -5.0 m/s in your equations. The sign convention would also apply to the acceleration due to gravity as shown above. The direction of the acceleration vector is down (-9.81 m/s2) because the gravitational force causing the acceleration is directed downward.

hope this info helps you out!

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Do you remember this formula for the distance traveled while accelerated ?

<u>Distance = (initial speed) x (t)  plus  (1/2) x (acceleration) x (t²)</u>

I think this is exactly what we need for this problem.

initial speed = 20 m/s down
acceleration = 9.81 m/s² down
t = 3.0 seconds

Distance down = (20) x (3)  plus  (1/2) x (9.81) x (3)²

Distance = (60)  plus  (4.905) x (9)

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Choice  <em>D)</em>  is the closest one.
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A 0.12-kg metal rod carrying a current of current 4.1 A glides on two horizontal rails separation 6.3 m apart. If the coefficien
Neporo4naja [7]

Answer:

The magnetic field is B  =  8.20 *10^{-3} \  T

Explanation:

From the question we are told that

   The  mass of the metal rod is  m  = 0.12 \ kg

    The current on the rod is  I  = 4.1 \ A

    The distance of separation(equivalent to length of the rod ) is L   = 6.3 \ m

     The coefficient of kinetic friction is \mu_k  =  0.18

      The kinetic frictional force is  F_k  = 0.212 \ N

     The constant speed is v  = 5.1 \ m/s

Generally the magnetic force on the rod is mathematically represented as  

      F  =  B * I  *   L

For  the rod to move with a constant velocity the magnetic force must be equal to the kinetic frictional force so

        F_ k  =  B*  I  *  L

=>      B  =  \frac{F_k}{L  *  I  }

=>       B  =  \frac{0.212}{ 6.3   *  4.1   }

=>       B  =  8.20 *10^{-3} \  T

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A straight wire in a magnetic field experiences a force of 0.023 N when the current in the wire is 2.5 A. The current in the wir
Tatiana [17]

Answer:

The new current in the wire is 6.3 A.

Explanation:

Given that,

Force in a straight wire, F = 0.023 N

Current in the wire, I = 2.5 A

If new force is, F' = 0.058 N, we need to find the new current.

We know that, magnetic force is given by :

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It is clear that force is directly proportional to electric current. So, we can say:

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3 years ago
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