Ask question

Ask question

All categories

4 years ago

6

Inertia ____.

1 answer:

OlgaM077 [116]4 years ago

4 0

The correct answer is (c.) resists a change in motion of an object. Inertia basically resists any physical changes in an object in terms of its state. As stated in the Newton's first law of motion or also known as law of inertia, an object that is at rest will stay at rest and an object that is in motion will stay in motion. In short, an object will keep doing what it is already doing UNLESS net force is acted upon it,

You might be interested in

Which factor affects gravitational potential energy but not elastic potential energy?

Oksana_A [137]

Mass....................

3 0

4 years ago

Read 2 more answers

PLEASE HELP!!!!!!!!!!!

Alexxandr [17]

I am 100% sure its A.

5 0

3 years ago

Read 2 more answers

An anchor with a density of 700 lb/ft3 tied to a rope is submerged in water (but is not touching the bottom). It has a volume of

Ivanshal [37]

Answer:

Explanation:

Given

Density of anchor $\rho _a=700\ lb/ft^3$

Volume of anchor $V=2.8\ ft^3$

Density of water $\rho _w=62.4\ lb\ft^3$

Buoyancy force on submerged object is given by

$F_B=\rho _W\times V\times g$

$F_B=62.4\times 2.8\times 32.2=5625.98\approx 5626\ approx lbf$

3 0

4 years ago

. A block of mass 4.0 kg on a spring has displacement as a function of time given by, x (t) = (1.0 cm) cos [(2.0 rad/s) t + 0.25

svlad2 [7]

Answer and Explanation:

1. Evaluate the function x(t) at t=0.5

$x(t)=1cos(2t+0.25)\\x(0.5)=cos(2*0.5+0.25)=cos(1+0.25)=cos(1.25)=0.3153223624\approx0.31cm$

2. The period of motion T can be calculated as:

$T=\frac{2\pi}{\omega}$

Where:

$\omega=2rad/s$

So:

$T=\frac{2\pi}{2}=\pi\approx3.14s$

3. The angular frequency can be expressed as:

$\omega=\sqrt{\frac{k}{m} }$

Solving for k:

$k=(\omega)^2*m=(2)^2*4=4*4=16\frac{N}{m}$

4. Find the derivate of x(t):

$\frac{dx}{dt} =v(t)=-2sin(2t+0.25)$

Now, the sine function reach its maximum value at π/2 so:

$2t+025=\frac{\pi}{2}$

Solving for t:

$t=\frac{\frac{\pi}{2} -0.25}{2} =0.6603981634s$

Evaluating v(t) for 0.6603981634:

$v(0.6603981634)=-2sin(2*0.6603981634+0.25)=-2sin(\frac{\pi}{2} )=-2*1=2$

So the maximum speed of the block is:

$v(0.6603981634)=2cm/s=0.02m/s$

In the negative direction of x-axis

5. The force is given by:

$F=kx$

The cosine function reach its maximum value at 2π so:

$2t+0.25=2\pi$

Solving for t:

$t=\frac{2\pi-0.25}{2} =3.016592654s$

Evaluating x(t) for 3.016592654:

$x(3.016592654)=cos(2*3.016592654+0.25)=cos(2\pi)=1cm=0.01m$

Therefore the the maximum force on the block is:

$F=16*0.01=0.16N$

6 0

3 years ago

What cause down syndrome

Marrrta [24]

Missing Chromosomes! xD

Weird Question!

3 0

4 years ago

Read 2 more answers