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AVprozaik [17]
2 years ago
6

You start driving north for 9 miles, turn right , and drive East for another 40 miles. At the end of driving, what is your staig

ht line distance from your starting point?
Physics
1 answer:
Tema [17]2 years ago
3 0

Answer:

41 miles

Explanation:

Also, the straight line distance from your starting point is technically called your displacement.

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Calculate the mass of a gas with a density of 0.0065 g/cm3 and volume of 260 cm3
Anuta_ua [19.1K]
\sf Density = \frac{mass}{volume }\\\\0.0065 =  \frac{mass}{260} \\\\{\boxed {\sf {mass =1.69 ~grams}}
6 0
2 years ago
Two satellites A and B orbit the Earth in the same plane. Their masses are 5 m and 7 m, respectively, and their radii 4 r and 7
Dmitry [639]

Answer:

The ratio of their orbital speeds are 5:4.

Explanation:

Given that,

Mass of A = 5 m

Mass of B = 7 m

Radius of A = 4 r

Radius of B = 7 r

The orbital speed of satellite A,

v_{A}=\sqrt{\dfrac{GM_{A}}{R_{A}}}......(I)

The orbital speed of satellite B,

v_{B}=\sqrt{\dfrac{GM_{B}}{R_{B}}}......(I)

We need to calculate the ratio of their orbital speeds

Using equation (I) and (II)

\dfrac{v_{A}}{v_{B}}=\sqrt{\dfrac{\dfrac{GM_{A}}{R_{A}}}{\dfrac{GM_{B}}{R_{B}}}}

Put the value into the formula

\dfrac{v_{A}}{v_{B}}=\sqrt{\dfrac{G\times5m\times7r}{G\times7m\times4r}}

\dfrac{v_{A}}{v_{B}}=\dfrac{5}{4}

Hence, The ratio of their orbital speeds are 5:4.

8 0
2 years ago
(ii) Describe how the acceleration of the train at time t = 100 s differs from the acceleration
quester [9]

Explanation:

Acceleration is the rate of change of velocity with time. When acceleration increases a body moves a faster velocity.

  • In the graph acceleration at time t= 100s is rapidly increasing.
  • At t = 20s, the acceleration of the body is getting started up.

A vehicle at time 100s will have a faster velocity compared to one at t = 20s

7 0
3 years ago
If a ping pong ball and a golf ball are both moving in the same direction with the same amount of kinetic energy, the speed of t
Liono4ka [1.6K]

If the kinetic energy of each ball is equal to that of the other,
then

(1/2) (mass of ppb) (speed of ppb)² = (1/2) (mass of gb) (speed of gb)²

Multiply each side by 2:

      (mass of ppb) (speed of ppb)² = (mass of gb) (speed of gb)²

Divide each side by (mass of gb) and by (speed of ppb)² :

     (mass of ppb)/(mass of gb)  =  (speed of gb)²/(speed of ppb)²

Take square root of each side:

       √ (ratio of their masses)  =  ( 1 / ratio of their speeds)²

By trying to do this perfectly rigorously and elegantly, I'm also
using up a lot of space and guaranteeing that nobody will be
able to follow what I have written.  Let's just come in from the
cold, and say it the clear, easy way:

If their kinetic energies are equal, then the product of each
mass and its speed² must be the same number.

If one ball has less mass than the other one, then the speed²
of the lighter one must be greater than the speed² of the heavier
one, in order to keep the products equal.

The pingpong ball is moving faster than the golf ball.

The directions of their motions are irrelevant.

5 0
3 years ago
I WILL GIVE BRAINLIEST
Vaselesa [24]
<h2><u>Answer:</u></h2><h2>A. Displacement</h2><h2>B. Time</h2><h2 /><h2>Your Welcome ❤</h2>
3 0
2 years ago
Read 2 more answers
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