Answer:
26:26
Step-by-step explanation:
I hope I've helped :)
Answer:
The probability that exactly 19 of them are strikes is 0.1504
Step-by-step explanation:
The binomial probability parameters given are;
The probability that the pitcher throwing a strike, p = 0.675
The probability that the pitcher throwing a ball. q = 0.325
The binomial probability is given as follows;

Where:
x = Required probability
Therefore, the probability that the pitcher throws 19 strikes out of 29 pitches is found as follows;
The probability that exactly 19 of them are strikes is given as follows;
Hence the probability that exactly 19 of them are strikes = 0.1504
Answer:
6 units above the x-axis
Step-by-step explanation:
The pair (9,6) are a set of coordinates that indicate how far away from the origin (0,0) the point is.
The coordinates are written (x,y) where 'x' is how far to the left or right of the y-axis (vertical) the point is. The 'y' is how far above or below the x-axis (horizontal) the point is.
So in this case, the set of (9,6) means that the point is located at 9 units to the right of the origin and the y-axis and 6 units above the x-axis
Answer:
3/4
Step-by-step explanation:
There are 12 marbles in the bag
9 marbles are not blue
P(not blue) = marbles that are not blue / total marbles
= 9/12 = 3/4
![\bf \textit{Logarithm Cancellation Rules} \\\\ \stackrel{\stackrel{\textit{we'll use this one}}{\downarrow }}{log_a a^x = x}\qquad \qquad a^{log_a x}=x~\hfill\stackrel{recall}{ln=log_e}\qquad log_e(e^z)=z \\\\[-0.35em] \rule{34em}{0.25pt}](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ctextit%7BLogarithm%20Cancellation%20Rules%7D%20%5C%5C%5C%5C%20%5Cstackrel%7B%5Cstackrel%7B%5Ctextit%7Bwe%27ll%20use%20this%20one%7D%7D%7B%5Cdownarrow%20%7D%7D%7Blog_a%20a%5Ex%20%3D%20x%7D%5Cqquad%20%5Cqquad%20a%5E%7Blog_a%20x%7D%3Dx~%5Chfill%5Cstackrel%7Brecall%7D%7Bln%3Dlog_e%7D%5Cqquad%20log_e%28e%5Ez%29%3Dz%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%20)

and you plug that in your calculator to get about -0.27465307216702742285.