All categories

3 years ago

HELP ME PLEASE I NEED THE ANSWER NOW

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

8 0

Answer:

132 cm^2

Step-by-step explanation:

Find all areas and add together.

A = L x W

tA = (L x W)/2

30 + 30 + 48 + 12 + 12 = 132

You might be interested in

Using the triangle below, find the length of side c if side a is 15 and θ =55. Round your answer to the nearest tenth.

Kaylis [27]

Answer:

15 sin 55 = 12

Step-by-step explanation:

It is a basic trigonometry formula

5 0

3 years ago

What is the best unit to describe the rate at which water flows through a household faucet

andrew11 [14]

The answer should be gallons per minute

5 0

3 years ago

The height h(n) of a bouncing ball is an exponential function of the number n of bounces.

Digiron [165]

Answer:

The height of a bouncing ball is defined by $h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$ .

Step-by-step explanation:

According to this statement, we need to derive the expression of the height of a bouncing ball, that is, a function of the number of bounces. The exponential expression of the bouncing ball is of the form:

$h = h_{o}\cdot r^{n-1}$ , $n \in \mathbb{N}$ , $0 < r < 1$ (1)

Where:

$h_{o}$ - Height reached by the ball on the first bounce, measured in feet.

$r$ - Decrease rate, no unit.

$n$ - Number of bounces, no unit.

$h$ - Height reached by the ball on the n-th bounce, measured in feet.

The decrease rate is the ratio between heights of two consecutive bounces, that is:

$r = \frac{h_{1}}{h_{o}}$ (2)

Where $h_{1}$ is the height reached by the ball on the second bounce, measured in feet.

If we know that $h_{o} = 6\,ft$ and $h_{1} = 4\,ft$ , then the expression for the height of the bouncing ball is:

$h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$

The height of a bouncing ball is defined by $h(n) = 6\cdot \left(\frac{4}{6} \right)^{n-1}$ .

5 0

3 years ago

Read 2 more answers

Round 832 to the nearest hundreds place.

elena-s [515]

Answer:

800

Step-by-step explanation:

Look at the tens if it's 0-4 keep the number the same if 5-9 go up one number

6 0

3 years ago

Read 2 more answers

A data set includes 103 body temperatures of healthy adult humans having a mean of 98.1 F and a standard deviation of 0.56 F. Co

Ira Lisetskai [31]

Answer:

The 99% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

Step-by-step explanation:

The first step is finding the confidence interval

The sample size is 103.

The first step to solve this problem is finding how many degrees of freedom there are, that is, the sample size subtracted by 1. So

$df = 103-1 = 102$

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.99}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 102 and 0.005 in the t-distribution table, we have $T = 2.63$ .

Now, we need to find the standard deviation of the sample. That is:

$s = \frac{0.56}{\sqrt{103}} = 0.055$

Now, we multiply T and s

$M = T*s = 2.63*0.055 = 0.145$

For the lower end of the interval, we subtract the mean by M. So 98.1 - 0.145 = 97.955F.

For the upper end of the interval, we add the mean to M. So 98.1 + 0.145 = 98.245F.

The 99% confidence interval estimate of the mean body temperature of all healthy humans is (97.955F, 98.245F).

98.6F is above the upper end of the interval, which means that the sample suggests that the mean body temperature could be lower than 98.6F.

5 0

3 years ago