Answer: As in other higher vertebrates, the frog body may be divided into a head, a short neck, and a trunk (see Vertebrates). The flat head contains the brain, mouth, eyes, ears, and nose. A short, almost rigid neck permits only limited head movement. The stubby trunk forms walls for a single body cavity, the coelom.
Explanation:
Answer:
The eukaryotes, bacteria, and archaea that live in and on the human body are called normal microbiota. When they were originally discovered, scientists thought that the relationship between these organisms was parasitic because they thought that the organisms benefit from living on the host but did not help the host. In recent years, researchers have determined that most of our resident microbes derive and give benefit to the host. This makes the relationship between host and microbe one of mutualism. Pathogenic, on the other hand, are microbes that cause diseases.
Answer:
C)
Explanation:
separation of the enzyme and the products of the reaction.
D because anashphere is were they are pulling apart
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Answer:
(a) 0.16
(b) 1
Explanation:
Let Probability that ticks in the Midwest carried Lyme disease, P(L) = 0.16
Probability that ticks in the Midwest carried HGE disease, P(H) = 0.10
Probability that ticks in the Midwest carried either Lyme disease or HGE disease, P(
) = 0.10
(a) Probability that a tick carries both Lyme disease (L) and HE (H) is given by
P(L 
H);
As we know that P(A 
B) = P(A) + P(B) - P(A B)
So, in our question;
P(L H) = P(L) + P(H) - P(L H)
0.10 = 0.16 + 0.10 - P(L H)
P(L H) = 0.16 + 0.10 - 0.10 = 0.16
Therefore, the probability that a tick carries both Lyme disease (L) and HE (H) is 0.16 or 16% .
(b) <em>Conditional Probability P(A/B) is given by</em> = 
So, the conditional probability that a tick has HE given that it has Lyme disease is given by = P(H/L)
P(H/L) = 
= 
= 1 .
