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4 years ago

Help please, I'm having so much trouble! It's quite easy!

Mathematics

1 answer:

amm18124 years ago

3 0

This would be your answer

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yawa3891 [41]

Answer:

The amount depositied is less than or equal to the amount of money in his wallet.

Step-by-step explanation:

PLEASE GIVE mE BRA1NL1EST!!!

7 0

3 years ago

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The distance between Lexington and Fayetteville is 2/3 as long as the distance between Lexington and booneville .If Lexington is

Fantom [35]

Answer:

The answer to your question is: 72 miles

Step-by-step explanation:

Data

Distance from Lexington from Fayetteville = 2/3 as distance Lexington and Booneville.

Distance Lexington to Fayetteville = 108 miles

Process

108 / 3 = 36 miles

36 x 2 = 72 miles

2/3 of 108 miles is 72 miles

The distance from Lexington to Fayetteville = 72 miles

3 0

3 years ago

Explain how to use working backwards for two different types of problems.

Marina CMI [18]

If you have an equation like 4 + w = 12, you'll work backward to find w by subtracting 4 from 12.

Or if you have an equation like 4r = 24, you'll work backward by dividing 24 by 4 to find r.

5 0

4 years ago

Can you help me solve 4x+3+x-8

Svetlanka [38]

The answer to your problem is -1x.

6 0

3 years ago

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Suppose astronomers built a 50-meter telescope. how much greater would its light-collecting area be than that of the 10-meter ke

drek231 [11]

Answer: Its light-collecting area would be 25 times greater than that of the 10-meter keck telescope.

Step-by-step explanation:

1. To solve this problem you must apply the formula for calculate the area of a circle, which is shown below:

$A=r^{2}\pi$

Where<em> r</em> is the radius of the circle.

2. The diameter of a circle is:

$D=\frac{r}{2}$

Where <em>r</em> is the radius of the circle.

3. Therefore, keeping this on mind, you have that the light-collecting area of a 50-meter keck telescope is:

$A_1=(\frac{50m}{2})^{2}\pi=1963,49m^{2}$

4. And the light-collecting area of a 10-meter keck telescope is:

$A_2=(\frac{10m}{2})^{2}\pi=78.53m^{2}$

5. Divide $A_1$ by $A_2$ , then:

$\frac{1963.49m^{2}}{78.53m^{2}}=25$

6. Therefore, its light-collecting area would be 25 times greater than that of the 10-meter keck telescope.

4 0

4 years ago