Question

A solution is 0.0433 m lif. what is the molarity of the solution if the density is 1.10 g/ml

Answer 1

Molarity is the number of moles of solute in one liter of solution whereas molality is the number of moles of solute present in 1 kilo gram of solution.

Molarity is denoted by M and molality denoted by m

$m = (n) * (1000 /w_A) = 0.0433 m$

$M_B = 26 g /mol$

$W_A = 1 kg = 1000 g$

$(W_B /26) * (1000 /1000) = 0.0433$

$W_B = 1.12 g$

Mass of solution

$W_B + W_A = 1.12 + 1000 = 1001.12 g$

Density of solution  = 1.1 g /mL

d = 1.1 = (W_B + W_A) /V  

$1.1 = (1001.12) /V$

V = 910.11 mL

molarity of solution is:

$M = (n) * (1000 /V)$

= 0.0433 /0.910 = 0.0474 M

Thus, moalrity of solution is 0.0474 M