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Colt1911 [192]
3 years ago
7

A particle moves in the xy plane, starting from the origin at t=0 with initial velocity having an x component of 20 m/s and a y

component of -15 m/s. The particle experiences an acceleration in the x direction, given by a x= 4.0 m/s2.
a) Determine the total velocity vector at any time.

b) Calculate the velocity and speed of the particle at t = 5.0 sec.
Physics
1 answer:
777dan777 [17]3 years ago
5 0

Answer:

a. \vec{v} = \vec{v_x} + \vec{v_y} = (20 + 4t)\hat{x} - 15 \hat{y}

b. 25m/s

Explanation:

Let t be the time.

The velocity in the x direction that is subjected to acceleration of 4 m/s2

v_x = 20 + 4t m/s

The velocity in the y direction

v_y = -15 m/s

The total velocity at any time, which is the combination of both x and y vectors of velocity

\vec{v} = \vec{v_x} + \vec{v_y} = (20 + 4t)\hat{x} - 15 \hat{y}

b) at t = 5

v^2 = v_x^2 + v_y^2 = (20 + 4t)^2 + 15^2 = (20 + 4*5)^2 + 15^2 = 400^2 + 225 = 625

v = \sqrt{625} = 25 m/s

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