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zhenek [66]
3 years ago
11

A car owner forgets to turn off the headlights of his car while it is parked in his garage. If the 12.0-V battery in his car is

rated at 51.0 A · h and each headlight requires 27.0 W of power, how long will it take the battery to completely discharge?
Physics
1 answer:
avanturin [10]3 years ago
3 0

Answer: 22.6 hours

Explanation:

The power is the measure of the rate of energy.

In this problem, the 12.0 V battery is rated at 51.0 Ah, which means it delivers 51.0 A of current in a time of t = 1 h = 3600 s. The power delivered by the battery can be written as

P=IV

where

I is the current

V = 12.0 V is the voltage of the battery

So the energy delivered by the battery can be written as

E=Pt=VIt

Where

It=51.0 A\cdot h = 51.0 A \cdot 3600 s/h=183,600 A\cdot s

So the energy delivered is

E=(12.0)(183,600)=2.2\cdot 10^6 J

At the same time, the headlight consumes 27.0 W of power, so 27 Joules of energy per second; Therefore, it will remain on for a time of:

t=\frac{2.2\cdot 10^6 J}{27.0 W}=81481 s = 22.6 h

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At time t1 = 14 s, a car is located at 99, 80, 27 m and has velocity 4, 0, −3 m/s. At time t2 = 18 s, what is the position of th
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Answer:

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Answer:

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