3 years ago

Please help me with this Physics question?

1 answer:

6 0

C 82.4 N sorry man if i am wrong but don't even think about reporting my answer

You might be interested in

aksik [14]

Answer: its 50

Explanation:

im waffling does anybody have syrup

4 0

3 years ago

hjlf

4848484 5 5 5 5 5 =++++

6 0

3 years ago

Ilya [14]

please mark this answer as brainlist

7 0

3 years ago

Ierofanga [76]

Answer:

......................

8 0

3 years ago

Tanzania [10]

To calculate the acceleration of the truck, we use the equation of motion

$v = u + at$

Here, v is final velocity of the truck, u is initial velocity of truck, a is acceleration of the truck and t is time taken.

Given, u = 6 m/s, v = 14 m/s and t = 4 s.

Substituting these values in above equation, we get

$14 \ m/s = 6 \ m/s + a \times 4 \ s \\\\ a = \frac{14 \ m/s - 6 \ m/s}{ 4 \ s } = 2 \ m /s^2$ .

Thus, the truck acceleration is $2 \ m /s^2$

3 0

3 years ago