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-Dominant- [34]
3 years ago
10

The nuclear equation is incomplete. Superscript 239 Subscript 94 Baseline P u + Superscript 1 Subscript 0 Baseline n yields Supe

rscript 100 Subscript 40 Baseline Z r + blank + 2 Superscript 1 Subscript 0 Baseline n What particle completes the equation?
Physics
1 answer:
Crank3 years ago
3 0

Answer:

The particle which completes the given equation  is :_{54}^{138}\textrm{Xe}

Explanation:

The given reaction is of a fission reaction:

_{94}^{239}\textrm{Pu}+_0^1\textrm{n}\rightarrow _{40}^{100}\textrm{Zr}+_Z^A\textrm{X}+2_0^1\textrm{n}

Total mass on the reactant side is equal to the total mass on the product side:

239 + 1 = 100 +A+ 2

A = 138

Sum of atomic numbers on the reactant side is equal to the sum of atomic number on the product side:

94 + 1(0) = 40 + Z + 2(0)

Z = 54

So atomic number 54 id of Xenon.

The particle which completes the given equation  is :

_{94}^{239}\textrm{Pu}+_0^1\textrm{n}\rightarrow _{40}^{100}\textrm{Zr}+_{54}^{138}\textrm{Xe}+2_0^1\textrm{n}

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5 0
3 years ago
What is time taken by the stone ?
SSSSS [86.1K]

The time taken by the stone to hit the ground would be 5.12 seconds.

<h3>What are the three equations of motion?</h3>

There are three equations of motion given by  Newton

The first equation is given as follows

v = u + at

the second equation is given as follows

S = ut + 1/2×a×t²

the third equation is given as follows

v² - u² = 2×a×s

Keep in mind that these calculations only apply to uniform acceleration.

As given in the problem, a stone is dropped from the helicopter which is ascending at the speed of 19.6 m/s

height(S) = 156.8 meters

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By using the second equation of motion given by newton

S = ut + 1/2at²

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156.8= -19.6t + 9.81t²

t = 5.12 seconds

Thus, the time taken by the stone to hit the ground would be 5.12 seconds.

Learn more about equations of motion from here,

brainly.com/question/5955789

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8 0
2 years ago
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So, v_g_3

5 0
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