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Damm [24]
3 years ago
10

How much heat is required to convert solid ice with a mass of 985 g and at a temperature of -29.5 °c to liquid water at a temper

ature of 81.5 °c? (the specific heat of ice is cice = 2100 j/kgk, the specific heat of water is cwater = 4186.8 j/kgk, and the heat of fusion for water is: lf = 334 kj/kg.)?

Physics
1 answer:
liberstina [14]3 years ago
6 0

Consider, please, this solution:

The final heat is:

Q=Q₁+Q₂+Q₃≈726.116 kJ

All the details are in the attachment.

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When measuring speed, you will measure the
qaws [65]

Answer:

Speed is the rate at which an object's position changes, measured in meters per second. The equation for speed is simple: distance divided by time

Explanation:

5 0
3 years ago
A 1.5 kg ball is thrown upward at 10 m/s. What is its velocity when it is 2 m above the release point?
Anestetic [448]

Answer:

7.75m/s or 2\sqrt{15}m/s

Explanation:

m = 1.5kg

u= 10m/s

s = 2m

a = 10m/s^{2}

v = ?

acceleration due to gravity is negative when an object is going up because the force of gravity reduces the speed of the object

using the formula ;

v^{2} = u^{2} - 2as since the object is moving upwards (negative acceleration)

= 100 - 2(10)(2)

100 - 40

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v = \sqrt{60}

= 7.75m/s

5 0
3 years ago
How does earths rotation affect life on earth
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3 years ago
Siska hit a golf ball into the air with an initial velocity of 56 feet per second. The height h in feet of the ball above the gr
olasank [31]
To find the time it takes for the ball to reach the given height, we need an equation that relates the height and time it travel which is given to be <span>h=-16t^{2}+56t. We just substitute the height of 49 feet then solve for t. We do as follows:

</span><span>h=-16t^{2}+56t
49 = </span>-16t^{2}+56t
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Hope this answers the question. Have a nice day.
4 0
3 years ago
Read 2 more answers
A gas undergoes two processes. In the first, the volume remains constant at 0.200 m3 and the pressure increases from 1.00×105 Pa
Alborosie
<h2>The work done = - 2 x 10⁴ J</h2>

Explanation:

In the first case , the volume is kept constant and pressure varies .

In isothermal process  , the work done

W₁ = V x ΔP

here V is the volume of gas and ΔP is the change in pressure

Thus W₁ = 0

Because there is no change in volume , therefore displacement is zero .

In second case pressure is constant , but volume changes

Thus W₂ = P x ΔV

here P is the pressure  and ΔV is the change in volume

Therefore W₂ = 4 x 10⁵ x 5 x 10⁻² = 2 x 10⁴ J

The total work done W = - 2 x 10⁴ J

Because the work done in compression is negative .

7 0
3 years ago
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