How much heat is required to convert solid ice with a mass of 985 g and at a temperature of -29.5 °c to liquid water at a temper
ature of 81.5 °c? (the specific heat of ice is cice = 2100 j/kgk, the specific heat of water is cwater = 4186.8 j/kgk, and the heat of fusion for water is: lf = 334 kj/kg.)?
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Answer:
Explanation:
So, we are looking for an expression of the amount of water that has been drained from the tub. The expression is in terms of v that represent the number of gallons of water drained since the plug was pulled. Since we are interested in the pounds of water that has been drained from the tub we need to take into account that for every gallon of water drained, 8.345 pounds have left the tub. Therefore, the expression for the weight of water Q that has been drained from the tub in terms of v is simply :
Where v is the amount of gallons that has been drained from the tub.
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