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faltersainse [42]
3 years ago
8

Which of the following has the same unit as the moment of force?

Physics
2 answers:
saw5 [17]3 years ago
6 0

Answer:

Work

Explanation:

Units are

kg {m}^{2}  {s}^{ - 2}  = newtons \times meter

Scilla [17]3 years ago
4 0
The answer is b- work
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A jogger jogs around a circular track with a diameter of 275 m in 14.0 minutes. what was the jogger's average speed in m/s?
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The jogger's average speed 1.03 m/s

<h3>The Speed and the Velocity of a Particle in a Circle</h3>

The speed of a particle is a circle will always be constant while the velocity will not. That is, velocity varies.

Given that a jogger jogs around a circular track with a diameter of 275 m in 14.0 minutes. First convert the minutes to seconds

Given parameters are;

  • Diameter = 275 m
  • Radius r = D/2 = 137.5 m
  • Time t = 14 minutes = 14 x 60s = 840 s

Speed V = 2πr ÷ t

V = ( 2 × π × 137.5 )  ÷ 840

V = 863.9 / 840

V = 1.028 m/s

Therefore, the jogger's average speed 1.03 m/s approximately

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Explain how sociology will contribute to the understanding of daily life and what is happening within it?
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Explain how sociology will contribute to the understanding of daily life and what is happening within it?

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A massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface. The mass hang
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Both masses will have the same acceleration. The cart accelerates to the right with a magnitude of 4.9 m/s^{2}. The correct answer is 4.90 m/s^{2}

Given that a massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface.

Let M = 1kg and m = 3 kg

Since the horizontal surface is frictionless, the tension in the string will be the same. when the mass is hanged over a frictionless pulley, the tension will also be the same.

When the mass is released, the cart accelerates to the right can be calculated  from Newton' second law of motion. That is,

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Therefore, the cart accelerates to the right with a magnitude of 4.9 m/s^{2}. The correct answer is 4.90 m/s^{2}

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