Answer:
a= 2.667 m/s²
Explanation:
Given that
Initial velocity ,u= 2 m/s
Final velocity ,v= 10 m/s
Time taken ,t= 3 s
As we know that
v = u + at
a=Acceleration ,u=Initial velocity ,v= Final velocity ,t=time
Now by putting the values in the above equation
v = u + at
10 = 2 + a x 3
8 = 3 a
a= 2.667 m/s²
Therefore the acceleration of the biker will be 2.667 m/s²
Answer and Explanation:
As per the question:
When the stone is thrown from the cliff top and hits the ground below eventually:
R =
where
= initial velocity
H = height
g = acceleration due to gravity
R = horizontal Range
Now,
(a) Displacement of the stone is given by the horizontal range:
R =
where
= initial velocity
H = height
g = acceleration due to gravity
R = horizontal Range
(b) Speed just prior to the impact is given by the third equation of motion:
where
v = final velocity
(c) Time of flight is given by the second eqn of motion where the initial velocity is considered to be 0 then:
T =
Answer: 0.04 s
Explanation:
The given equation for the period of a pendulum when the acceleration due gravity is given in feet per squared second
is:
Where is the length of the pendulum