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leva [86]
3 years ago
10

Will Give Brainlist Check pic for question

Physics
2 answers:
Harrizon [31]3 years ago
5 0
Ohms law = v= Ir

V= 0.02 x 4000 = 80v
KIM [24]3 years ago
4 0

Answer:

D: 80v is the anwser to the question

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Pls answerrr it's urgent!!!!!
lilavasa [31]

Explanation:

the average velocity of the car is 15 m/s example I have this on a test

6 0
2 years ago
Your friend is wearing a red coat. When white light hits the coat, some light is reflected, and some is absorbed.
Vilka [71]

Answer:

Orange , yellow, green and blue

red coat absorbs all colors of visible light except red, so red light

is the only light left to bounce off of the coat toward our eyes.

4 0
2 years ago
What is the formula of the compound between calcium and sulfur that has the percent composition 55.6?
Yanka [14]

CaS is the empirical formula of the compound between calcium and sulphur that has the percent composition 55.6.

When percentages are given, we take a total mass of 100 grams.

Therefore the mass of each element is equal to the percentage given.

Mass of Ca = 55.6 g (given) of

S Mass = 44.4 g (100 - 55.6 = 44.4)

Step 1: Convert the given mass to moles.

moles Ca = given mass Ca / molar mass Ca

moles = 55.6 / 40 = 1.39 moles

mol S = specific mass S / molar mass S

mol = 44.4 / 32 = 1.39 mol

Step 2: Divide the molar ratio of each molar value by the smallest number of moles calculated.

For Ca = 1.39 / 1.39 = 1

For S = 1.39 / 1.39 = 1

The ratio of Ca : S = 1:1

Hence the empirical formula of the given compound will be CaS.

Learn more about empirical formula here : brainly.com/question/1496676

#SPJ4

8 0
1 year ago
Some liquid is poured into a burrete so that it reads 14cm³.50 drops were run each of volume 0.1cm³ .
nika2105 [10]

Given :

Liquid is poured into a burrete so that it reads 14cm³.

50 drops were run each of volume 0.1cm³ .

To Find :

The volume of liquid in burrete after 50 drops.

Solution :

Volume of each drop, v = 0.1 cm³.

Initial volume in burrete, V = 14 cm³.

Now, volume left after droping 50 drops are :

L = V - 50v\\\\L = 14 - 50\times 0.1 \ cm^3 \\\\L = 9 \ cm^3

Therefore, the volume left in burrete is 9 cm³ .

5 0
3 years ago
Oil having a density of 926 kg/m3 floats on water. A rectangular block of wood 3.69 cm high and with a density of 974 kg/m3 floa
zloy xaker [14]

Answer:

the position of the wood below the interface of the two liquids is 2.39 cm.

Explanation:

Given;

density of oil, \rho _o = 926 kg/m³

density of the wood, \rho _{wood} = 974 kg/m³

density of water, \rho _w = 1000 kg/m³

height of the wood, h = 3.69 cm

Based on the density of the wood, it will position across the two liquids.

let the position of the wood below the interface of the two liquids = x

Let the wood be in equilibrium position;

F_{wood} - F_{oil} - F_{water} = 0\\\\\rho _{wood} .gh - \rho _o .g(h-x) - \rho_w .gx = 0\\\\\rho _{wood} .h - \rho _o (h-x) - \rho_w .x = 0\\\\\rho _{wood} .h -\rho _o h + \rho _o x - \rho_w .x =0\\\\h (\rho _{wood}  -\rho _o ) = x( \rho_w - \rho _o)\\\\x =h[\frac{ \rho _{wood}  -\rho _o }{\rho_w - \rho _o} ]\\\\x = 3.69\ cm \times [\frac{974 - 926}{1000-926} ]\\\\x = 2.39 \ cm

Therefore, the position of the wood below the interface of the two liquids is 2.39 cm.

6 0
3 years ago
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