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Debora [2.8K]
3 years ago
5

Tengo 200 panes y mi hermano se comió 100 cuantos me quedan?

Mathematics
1 answer:
ipn [44]3 years ago
5 0

Answer:

100

Step-by-step explanation:

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The sum of all three numbers is 12. The sum of twice the first number, 4 times the second number, and 5 times the third number i
grigory [225]

Answer:

The numbers are 7, 4 and 1

Step-by-step explanation:

Let the numbers =x, y, z.

The sum of all three numbers is 12, x+y+z=12--------i

The sum of twice the first number, 4 times the second number, and 5 times the third number is 35, 2x+4y+5z=35-------ii

The difference between 8 times the first number and the second number is 52, 8x-y=52---------iii

Now, from (i),z =1-x-y--------iv

substitute (iv) in (ii),

2x+4y+5(12-x-y)=35

2x+4y+60-5x-5y=35

collect like terms

-3x-y=-25

that is, 3x-y=25--------v

solving (iii) and (v) simultaneously (add iii and v), we have

11x=77

divide both sides by 11 to obtain x=7

Put x=7 in (v)

3(7)+y=25

21+y=25

implies y=25-21=4

put x=7 and y=4 in (iv)

z=12-7-4=1

Hence, the numbers are 7, 4 and 1.

5 0
3 years ago
Which of the following is a function and a relation?​
IrinaVladis [17]
A I hope this helps
4 0
2 years ago
WILL GIVE BRAINLYIST
marysya [2.9K]

Answer:

64 degrees

Step-by-step explanation:

Since the triangles are similar they have the same angle measures

\frac{PR}{PQ} =\frac{SU}{ST}          \frac{21}{14}= \frac{6}{4}

∠P = ∠S ∠R =∠U ∠Q=∠T

We know 2 of the angle measures: ∠S and ∠R, and since they are similar we know ∠P and ∠U

In triangles the sum of all angle measures is always 180 degrees, so we can solve for ∠Q with this formula

A+B+C=180

46+70+C+180

116+C=180

subtract 116 from both sides

C=64

Therefore ∠Q is equal to 64 degrees

3 0
3 years ago
If Kye can rollerblade 1.5 miles in 8 minutes how many miles does he rollerblade in 1 minute
mixer [17]

Answer:

0.1875 miles

Step-by-step explanation:

3 0
2 years ago
Help algebra 2 please
34kurt

Answer:

option 4

Step-by-step explanation:

(f*g)(x) =(x² + x+ 1)*(x² - x -1)

           = x²*(x² - x -1)   + x(x² - x -1) + 1*( x² - x -1)

            = x²*x² - x²*x -x²*1   + x*x² - x*x -x*1 + x² - x -1

            = x⁴ - x³ - x² +x³ - x²  - x  + x² - x -1

           = x⁴  - x³ + x³  - x² - x² + x² - x - x - 1

       = x⁴ - x² - 2x - 1

4 0
2 years ago
Read 2 more answers
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