Answer:
m₃ = 30 kg
Explanation:
This is a problem of rotational equilibrium, let's write Newton's law for rotational equilibrium.
Let's fix our reference system in the support, the positive torques are those that create an anti-clockwise turn
Let's look for the distances to the point of support
The distance of man
x₁ = -3 m
The distance of the bar is
x₂ = L / 2 -3
x₂ = 10/2 -3
x₂ = 2 m
Remote object at the end
x₃ = L-3
x₃ = 10-3
x₃ = 7 m
They give us the mass of man (m1) and the mass of the bar (m2)
Let's write the torques
W₁ x₁ - W₂ x₂ - w₃ x₃ = 0
m₁ g 3 - m₂ g 2 - m₃ g 7 = 0
m₃ = (3m₁ -2m₂) / 7
Let's calculate
m₃ = (3 80 -2 15) / 7
m₃ = 30 kg
<span>a solution is a liquid mixture </span>
The average velocity of the whole journey will be total distance covered divided by the total time. It will be approximately equal to 8 m/s. The right answer is option B
<h2>VELOCITY</h2>
Velocity is the distance travelled in a specific direction. While the average velocity of the whole journey will be total distance covered divided by the total time
When driving a Toyota avensis car along a straight road for 16.5km at
50km/h,
The velocity = 50 km/h
Distance = 16.5 km
Use the speed formula to calculate time.
Speed = distance / time
Time = distance / speed
Time = 16.5 / 50
Time = 0.33 s
If over the next 20min, you walked another 2.5km further along the road for a petrol station, Then,
average velocity = Total distance covered divided by total time taken.
Where
The time t = 20/60 = 0.333 h
Total time = 0.33 + 0.3333
Total time = 0.6633333
Total distance = 16.5 + 2.5
Total distance = 19 km
Average velocity = 19 / 0.66333
Average Velocity = 28.64 km/h
Now convert Km/h to m/s
(28.6432 x 1000) / 3600
286432 / 3600
7.956m/s
Therefore, the average velocity of the whole journey from beginning of the drive to the arrival at the filling station will be approximately 8 m/s
Learn more about velocity here: brainly.com/question/6504879
Answer:
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Explanation:
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We have that F=ma from the 2nd Newton law where F is the force, m is the mass and a is the acceleration. Suppose we have that F' is the new force and m' is the new mass. Then, we have that a'=F'/m' still, by rearranging Newton's law. We are given that F'=2F and m'=m/2. Hence,

But now, we have from F=ma, that a=F/m and we are given that a=1m/s^2.
We can substitute thus, a'=4a=4*1m/s^2=4m/s^2.