Question

A basketball referee tosses the ball straight up for the starting tip-off. At what velocity (in m/s) must a basket ball player leave the grownd to rist 1.24 m above the floor in an attempt to get the ball?

Answer 1

Answer:4.93 m/s

Explanation:

Given

height to reach is (h )1.24 m

here Let initial velocity is u

using equation of motion

$v^2-u^2=2ah$

here Final Velocity v=0

a=acceleration due to gravity

$0-u^2=2\left ( -g\right )h$

$u=\sqrt{2gh}$

$u=\sqrt{2\times 9.81\times 1.24}$

$u=\sqrt{24.328}$

u=4.93 m/s