1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
spin [16.1K]
3 years ago
14

Oil explorers set off explosives to make loud sounds, then listen for the echoes from underground oil deposits. Geologists suspe

ct that there is oil under 500-m-deep Lake Physics. It's known that Lake Physics is carved out of a granite basin. Explorers detect a weak echo 0.99 s after exploding dynamite at the lake surface. The speed of sound

Physics
2 answers:
Elenna [48]3 years ago
3 0

Answer:

dg= 942m

Explanation:

given the depth of the granite Us dg = 500m

time between the explosion t = 0.99s

the speed of sound in granite is Vg = 6000m/s

First of all calculate the time it takes the sound waves to travel down through the lake

Vw = dw/t1

t1 = dw/Vw

t1 = 500/1480

t1 = 0.338s.

Let dg be the depth of the granite basin, so the time it takes for the sound to travel down through the granite is t2 = dg/6000m/s......equation(1)

So the total time it takes to travel down to the oil surface will be

t1/2 = t1 + t2

t1/2=  0.338 + dg/6000.

since the reflection on the oil does not change the speed of sound, the sound will take travelling upto the surface the same time it takes to reach the oil

so; t = 2 t1/2

t1/2 = t/2 = 0.99s/2 = 0.495

Now insert into the values of t1/2 into the equation (1) and solve for dg;

we get 0.495 = 0.338 + dg/6000

dg = (0.495 - 0.338) x 6000

dg = 942m.

seraphim [82]3 years ago
3 0

Answer:

d(g) = 642m

Explanation:

Given the following data

Depth of the granite d(g) = 500m, the time within the explosion (t) = 0.99secs.

From the fixed parameters, Speed of sound of granite = 1600m/s and speed of sound in water = 1480m/s.

Since it takes 0.99secs time of echo after exploding dynamite at the lake surface at 500m deep lake water, we have to calculate the time it takes for the sound wave to travel down the water

T(w) =  d(w)/V(w) = 500/1480

T(w) = 0.388secs

d(g) is the Depth of the granite and we calculate this as

T(2) = d(g)/6000

Therefore, the total time it takes for oil to flow down is given as

To = T(1)+T(2) = 0.388+d(g)/6000....1

Since the reflection of the oil doesn't change speed of the sound, we have that T = 2To

To = t/2 = 0.99/2

To = 0.495secs

Now, we plug in the values into equation 1

0.495 = 0.388+d(g)/6000

0.495-0.388 = d(g)/6000

0.107×6000 = d(g)

d(g) = 642m

You might be interested in
Please helo me to 1st question<br>​
k0ka [10]

Explanation:

6 min in seconds:

6×60

<h2><u>360</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u>s</u><u> </u></h2><h2 /><h2 />

6 min in hours:

<h2><u>0</u><u>.</u><u>1</u><u> </u><u>hours</u></h2>
6 0
3 years ago
A 1640 kg merry-go-round with a radius of 7.50 m accelerates from rest to a rate of 1.00 revolution per 8.00 s. Estimate the mer
son4ous [18]

Solution :

Given data :

Mass of the merry-go-round, m= 1640 kg

Radius of the merry-go-round, r = 7.50 m

Angular speed, $\omega = \frac{1}{8}$  rev/sec

                             $=\frac{2 \pi \times 7.5}{8}$  rad/sec

                              = 5.89 rad/sec

Therefore, force required,

$F=m.\omega^2.r$

   $$=1640 \times (5.89)^2 \times 7.5  

   = 427126.9 N

Thus, the net work done for the acceleration is given by :

W = F x r

   = 427126.9 x 7.5

   = 3,203,451.75 J

6 0
2 years ago
Question 1<br> 2 pts<br> Explain what causes a solution to be a strong acid.
lubasha [3.4K]

Answer:

Cuanto más fuerte es el ácido, más rápido se disocia para generar H +start superscript, plus, end superscript. Por ejemplo, el ácido clorhídrico (HCl) se disocia completamente en iones hidrógeno y cloruro cuando se mezcla con agua, por lo que se considera un ácido fuerte.

5 0
3 years ago
An airplane flies with a constant speed of 840 km/hr. How far will go in 270 min
inna [77]
3780 km.
..................
.....
........












5 0
3 years ago
Read 2 more answers
How much current is in a circult that includes a 9.0-volt battery and a bulb with a resistance of 4.0 ohms?
SVETLANKA909090 [29]

Answer:

Current, I = 2.3 A

Explanation:

We have,

Voltage of the battery in a circuit is 9 volts

Resistance of the circuit is 4 ohms

It is required to find the current in a circuit. When the voltage and the resistance of the circuit is given then we can find the current in it is given by Ohm's law as :

V=IR

I is electric current

I=\dfrac{V}{R}\\\\I=\dfrac{9}{4}\\\\I=2.25\ A

or

I = 2.3 A

So, the current in the circuit is 2.3 A.

6 0
3 years ago
Other questions:
  • Phylis Physics travels a displacement of 2.50 km north followed by 4.30 km south and then 1.40 km north. What is her final displ
    5·1 answer
  • 40 POINTS
    12·2 answers
  • A 150-loop coil of cross sectional area 6.3 cm2 lies in the plane of the page. An external magnetic field of 0.060 T is directed
    14·1 answer
  • Find the magnitude of the electric force on a 2.0 uC charge in a 100n/C electric field.
    15·1 answer
  • Calculate how much work you need to move the 130 N trunk to a ledge 2 m above.
    10·2 answers
  • A golf ball with an initial angle of 34° lands exactly 240 m down the range on a level course.
    11·2 answers
  • A small toy cart equipped with a spring bumper rolls toward a wall with a speed of v . The cart rebounds from the wall, with the
    9·1 answer
  • 10 turns of wire are closely wound around a pencil as shown in the figure. when measured using a scale as shown, the length of t
    8·1 answer
  • Container A and container B hold samples of the same ideal gas. The volume and the pressure of container A is equal to the volum
    8·1 answer
  • A long thing bar of copper is heated evenly along it's length
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!