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alex41 [277]
3 years ago
10

A capacitor is charged by a 150.0-V power supply, then disconnected from the power and connected in series with a 0.280-mH induc

tor. Calculate: (a) the oscillation frequency of the circuit; (b) the energy stored in the capacitor at time (the moment of connection with the inductor);
Physics
1 answer:
ololo11 [35]3 years ago
4 0

Frequency = 1 / (2π√LC)

Frequency = 1 / (2π · 2.8 x 10⁻⁴ · C)

Frequency = 1 / (1.759 x 10⁻³ · C)

<em>Frequency = (568.4 / C)  Hz.</em>

<em></em>

Energy stored in a capacitor = 1/2 C V²

Energy = 1/2 C · 2.25 x 10⁴

<em>Energy = (11,250 · C)  Joules</em>

<em></em>

Neither of the answers can be completely specified without knowing the value of the capacitor.

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The remaining variable must be the control variable. Unlike the previous variables, we can have more than one of these. The control variable is there to make sure that only the dependent variable is affecting the outcome. We do this by keeping the control variable the same through each trial, which is why the photographer should not change the type of bulb in the second experiment, changing only the color of the light.

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