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alex41 [277]
3 years ago
10

A capacitor is charged by a 150.0-V power supply, then disconnected from the power and connected in series with a 0.280-mH induc

tor. Calculate: (a) the oscillation frequency of the circuit; (b) the energy stored in the capacitor at time (the moment of connection with the inductor);
Physics
1 answer:
ololo11 [35]3 years ago
4 0

Frequency = 1 / (2π√LC)

Frequency = 1 / (2π · 2.8 x 10⁻⁴ · C)

Frequency = 1 / (1.759 x 10⁻³ · C)

<em>Frequency = (568.4 / C)  Hz.</em>

<em></em>

Energy stored in a capacitor = 1/2 C V²

Energy = 1/2 C · 2.25 x 10⁴

<em>Energy = (11,250 · C)  Joules</em>

<em></em>

Neither of the answers can be completely specified without knowing the value of the capacitor.

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Part A
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Answer:

2.5 m/s²

Explanation:

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a = 25/10 = 2.5 m/s²

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6. Two light bulbs are designed for use at 120 V and are rated at 75 W and 150 W. Which light bulb has the greater filament resi
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\\ \bull\tt\longrightarrow P=\dfrac{V^2}{R}

  • P is power
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\\ \bull\tt\longrightarrow R=\dfrac{V^2}{P}

Hence

\\ \bull\tt\longrightarrow R\propto V

\\ \bull\tt\longrightarrow R\propto \dfrac{1}{P}

  • Therefore if power is low then resistance will be high.

The first bulb has less power hence it has greater filament resistance.

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