Answer:
B₂
Explanation:
The limiting reactant is always a reactant. You can determine which reactant is limiting by identifying which has the smaller mole-to-mole ratio with the product. This ratio can be found via the coefficients of the balanced reaction.
4 A₂ + 3 B₂ ---> 6 AB
4 moles A₂
------------------ = mole-to-mole ratio A₂/AB
6 moles AB
3 moles B₂
------------------ = mole-to-mole ratio B₂/AB
6 moles AB
Since the mole-to-mole ratio between B₂ and AB is smaller, B₂ must be the limiting reactant.
Answer:
magnesium= +2
aluminum= +3
phosphorous= -3
lithium= +1
fluorine= -1
Explanation:
As fluorine having seven valance electrons in its outer most shell with atomic number nine. And for completing its outer most shell it needs one more electron that is why it form ion of -1 value.
Now Aluminum has three electrons in its outer most shell with atomic number 13. So it need to lose these three electrons in order to be in stable state that is why it have ion in +3 state.
Same rule apply for other elements too.
Answer:
cis-3-hexene and trans-3-hexene
Explanation:
Hydroboration oxidation is a method of preparation of alcohol from alkene.
Hydroboration follows anti-Markovnikoff rule in which alcohol group attached to less substituted carbon. Stereochemistry of the product is always syn that is H and OH attached to the same side of the double bond.
cis-3-hexene and trans-3-hexene undergoes hydroboration to form 3-hexanol.
Metallic (w) with a boiling point of 566”
Answer:
12 L of O₂
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
CS₂ + 3O₂ —> CO₂ + 2SO₂
From the balanced equation above,
3 L of O₂ reacted to produce 1 L of CO₂.
Finally, we shall determine the volume of O₂ required to produce 4 L of CO₂. This can be obtained as follow:
From the balanced equation above,
3 L of O₂ reacted to produce 1 L of CO₂.
Therefore, xL of O₂ will react to produce 4 L of CO₂ i.e
xL of O₂ = 3 × 4
xL of O₂ = 12 L
Thus, 12 L of O₂ is needed for the reaction.
